When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
The correct answer is (-2,1,2,8)
The range are the y- values
The explanation:
The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.
Hope this helped you :D
HOPE THIS IS THE ANSWER FOR YOUR QUESTION
Answer:
3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.
Step-by-step explanation:
3 is greater than -4, so strictly speaking, a slope of 3 is greater than a slope of -4.
On the other hand, the steepness of a line depends on the absolute value of the slope.
|3| = 3
|-4| = 4
Since 4 > 3, the line with slope -4 is steeper than the line with slope 3.
Answer: 3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.