1.C) -4a-8-a = -5a-8
2. C)-2 - x - 4.3= -6.3 -x
3.A) -2x+6-x-4= -3x+2
hope it helps
Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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I don’t know guat your sayin my friend my bad
Answer:
The answer: 1/10x (k-7)
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given: </u>
line y=3x-1
point (-3,0)
<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)
<u>Solution:</u>
The slope of the given line is 
If 
is the slope of perpendicular line, then
So, the equation of the needed line is 
Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:
