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Aleksandr [31]
3 years ago
7

How many single bonds would be needed to make an octet?

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer: it would be four

Step-by-step explanation:

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Question 23 HELP ME PLEASE Write an equation in slope-intercept from for the parallel to y=3x-2 that passes through the point (5
madreJ [45]

Answer:

y = 3x - 17

Step-by-step explanation:

Parallel lines have the same slope so the equation would be y = 3x + b

plugging in the points you get -2 = 3(5) + b

this is -17 = b

7 0
3 years ago
A dose of a new pharmaceutical drug is decaying according to the half-life model f(t) = Ne-0.2174, where N is the dose
Rudiy27

Answer:

  14.7

Step-by-step explanation:

Perhaps your equation is ...

  f(t) = N·e^(-0.2174t)

We want f(6) = 4, so ...

  4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N

  N = 4/0.2713 = 14.7 . . . . milligrams

The dose amount was about 14.7 mg.

6 0
4 years ago
There are 43 tiles in a bag. The colors are red, blue, green and yellow. Find the
ololo11 [35]

Answer:

43/13, 129/26, 129/13, 645/26

Step-by-step explanation:

Let w represent the number of red tiles, x represent the number of blue tiles, y represent the number of green tiles and z represent the number of yellow tiles. Hence:

w + x + y + z = 43    (1)

x = 3/5(w + x)

2x/5 = 3w/5

x = 3/2(w)  

x = 5w/2 - w = 3w/2  (2)

y = 2/3(x + y)

y/3 = 2x/3

y = 2x = 2(3w/2) = 3w    (3)

z = 5/7(y + z)

2/7(z) = 5y/7

z = 5y/2 = 5(3w)/2 = 15w/2   (4)

substitute x = 3w/2, y = 3w and z = 15w/2 in equation 1:

w + 3w/2 + 3w + 15w/2 = 43

13w = 43

w = 43/13

x = 129/26

y = 3w = 129/13

z = 645/26

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx-8%7D" id="TexFormula1" title="\sqrt[4]{x-8}" alt="\sqrt[4]{x-8}" align="abs
gavmur [86]
X=8 is the correct answer
3 0
3 years ago
Which sum or difference identity would you use to vertify that cos (180⁰- thata)=-cos thata <br>​
astraxan [27]

Step-by-step explanation:

Use the angle difference formula for cosine.

cos(α − β) = cos α cos β + sin α sin β

cos(180° − θ) = cos 180° cos θ + sin 180° sin θ

cos(180° − θ) = (-1) cos θ + (0) sin θ

cos(180° − θ) = -cos θ

3 0
3 years ago
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