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Ede4ka [16]
3 years ago
5

Complete the equation of the line through (-1,6) (7,-2) Like Y= ??

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-1, 6) and (7, -2). Substitute:

m=\dfrac{-2-6}{7-(-1)}=\dfrac{-8}{8}=-1\\\\y-6=-1(x-(-1))\\\\y-6=-(x+1)\\\\y-6=-x-1\qqiad|\text{add 6 to both sides}\\\\\boxed{y=-x+5}

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Answer these true or false questions:
stepan [7]
Sometimes it helps to put a number line in front of you. If one number is to the left of the other number on the number line, it's a lower number. If one number is to the right of the other number on the number line, it is greater.

-5 -4 -3 -2 -1 0 1 2 3 4 5

4 is a solution of x<-5
FALSE: 4 is not greater than -5


-3 is a solution of y>-2
FALSE: -3 is not greater than -2


y≤3 includes 3 as a possible solution
TRUE: 3 is less than OR EQUAL to 3


Hope this helps! :)
4 0
3 years ago
Find the x- and y-intercepts of the graph of the linear equation −x+8y=4
Andreyy89
First set the equation equal to y by adding x to each side, then divide everything by 8. then set x to zero and solve to find the y - intercept of 1/2 which is just 4/8 reduced. you get this answer because x/8 becoming 0/8 is just 0 leaving you with only 1/2. then reset the equation with x and set y to zero and solve for x to get the x- intercept of -4. you get this by subtracting 1/2 from both sides leaving you -1/2=x/8 and multiply by 8 to get -4=x

4 0
3 years ago
I am so confused please
sashaice [31]
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6 0
3 years ago
Read 2 more answers
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
Two parallel lines are crossed by a traversal. What is the value of b?
nika2105 [10]

Answer:

b = 128 answers it is alternate angle

7 0
3 years ago
Read 2 more answers
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