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3 years ago

A car is about 4 km long. 4 cm 4 m 4 g

Mathematics

1 answer:

Ivenika [448]3 years ago

4 0

Answer:

if they are choices then its 4 m

Step-by-step explanation:

it cant be the other ones

You might be interested in

What fraction of one day is 36 mins

Nezavi [6.7K]

Answer:

1 day = 1440min

so 36min of a day = 36/1440 = 1/40

3 0

2 years ago

For Jane Jones is a single person with 2 exemptions. In a week she earns $212.12. Using the chart above, Jane's federal income t

SpyIntel [72]

Answer:

The other answer is INCORRECT the CORRECT answer is : 34.00

Step-by-step explanation:

In the chart it shows how much for the number of exemptions. The other answer only included one but the question asks for TWO. Therefore making it 34.00

6 0

3 years ago

A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3

AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

$x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km$

Now, we can find the time when the trains will be 1520 km apart:

$1520 km = (x_{1} + 240 km) + x_{2}$

Where 1 is for the cargo train and 2 is for the passenger train.

$1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}$

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

$1520 km = (v_{1}*t + 240 km) + v_{2}t$

$t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h$

For the cargo train, it will be 1520 km apart from the passenger train at:

$t_{1} = 12 pm + 2 h + 40 min = 2:40 pm$

And for a passenger train, it will be 1520 km apart from the cargo train at:

$t_{2} = 2 pm + 2 h + 40 min = 4:40 pm$

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) The distance traveled by both trains is given by:

$x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km$

$x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km$

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!

5 0

2 years ago

A ball, thrown vertically upwards, from the ground, has its height h (in meters) expressed as a function of time t (in seconds),

Ivenika [448]

Answer:

pen

Step-by-step explanation:

fddefefgerf

6 0

3 years ago

Read 2 more answers

A woman walks due west on the deck of a ship at 3 mi/h. The ship is moving north at a speed of 22 mi/h. Find the speed and direc

Minchanka [31]

Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

Step-by-step explanation:

Since we have given that

Speed at which woman walks due west = 3 mi/hr

Speed at which ship moving due north = 22 mi/hr

Now it forms "Pythagorus theorem":

So, it becomes,

$H^2=B^2+P^2\\\\H^2=3^2+22^2\\\\H^2=9+484\\\\H^2=493\\\\H=\sqrt{493}\\H=22.20\ mi/hr$

And the direction of the woman relative to the surface of the water is given by

$\theta=\sin^{-1}x(\dfrac{3}{22.2})=7.76\approx 8^\circ$

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

5 0

3 years ago