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aleksandrvk [35]
3 years ago
15

A line has a slope of -2 and a y-intercept of –3. Graph the line using the slope and y-intercept.

Mathematics
2 answers:
masha68 [24]3 years ago
5 0

Answer:The answer is 231

Step-by-step explanation:

NARA [144]3 years ago
3 0

Answer:

it is 231

Step-by-step explanation:

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A grocery store purchases melons from two distributors, J & K. Distributor J provides melons from organic farms. The distrib
harina [27]

Answer: green.                

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The table shows the height of a plant as it grows.
viva [34]

Answer

144

Step-by-step explanation:

12*12

3 0
3 years ago
Can someone please explain how to do these?
Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

For the first limit, plug in x=8 in the expression (9x-3), that's the answer for linear equations and limits.

So we have:

9x-3\\9(8)-3\\72-3\\69

The answer is 69


For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5

So the answer is 5

3 0
3 years ago
What is 6x3/5 as a mixed number
Katen [24]
First, make 6 into an improper fraction.
6/1
Now multiply the numerators.
6x3=18
Now, the same with the denominators.
1x5=5
18/5
Now make it into a mixed number.
5x3=15
3 and...
18-15=3
3 and 3/5!!
Hope this helped!
8 0
3 years ago
For part A the choices are 25 and 34 and for part b it is 2 and 10
diamong [38]

Answer:

Part A is 34

Part B is 2

Step-by-step explanation:

This question did provide some clues to answer this question. Every week, the area covered by the algae is multiplied by 2^1.

To find the area cover increase by the algae per day, the exponent should be divided by 7 since there are 7 days in a week. Hence, every day, the area covered by the algae multiplies by 2^(1/7). In other words, 1 day after the algae was spotted, the area is 12.5 * 2^(1/7), which answers part B.

10 days after the algae was spotted, the area covered by the algae is 12.5 * 2^[(1/7)*10] = 33.6475... , which rounds up to 34 and answers part A.

5 0
2 years ago
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