Use the worked example above to help you solve this problem. A wire carries a current of 21.8 A from west to east. Assume that a
t this location the magnetic field of Earth is horizontal and directed from south to north and that it has a magnitude of 5.00 10-5 T. (a) Find the magnitude and direction of the magnetic force on a 38.1 m length of wire. N
1 answer:
Answer:
Themagnitude of the force is 0.0415N and is directed vertically upwards. The solution to this problem uses the relationship between the Force experienced by a conductor in a magnetic field, the current flowing through the conductor, the length of the conductor and the magnitude of the electric field vector.
Mathematically this can be expressed as
F = I × L ×B
Where F = Force in newtons N
I = current in ampres A
L = length of the conductor in meters (m)
B = magnetic field vector in T
Explanation:
The calculation can be found in the attachment below.
Thedirection of the force can be found by the application of the Fleming's right hand rule. Which states that hold out the right hand with the index finger pointing in the direction of the magnetic field and the thumb pointing in the direction of the current in the conductor, then the direction which the middle finger points is the direction of the force exerted on the conductor. By applying this the direction is vertically upwards.
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Answer:
The value is
Explanation:
From the question we are told that
The radius of the inner conductor is
The radius of the outer conductor is
The potential at the outer conductor is
Generally the capacitance per length of the capacitor like set up of the two conductors is
Here is the permitivity of free space with value
=>
=>
Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge
Generally the line charge density of the outer conductor is mathematically represented as
=>
=>
Generally the surface charge density is mathematically represented as
here
=>
=>
Answer:
0.36
Explanation:
The maximum force of friction exerted by the surface is given by:
(1)
where
is the coefficient of friction
N is the normal reaction
The shed's weight is 2200 N. Since there is no motion along the vertical direction, the normal reaction is equal and opposite to the weight, so
N = 2200 N
The horizontal force that is pushing the shed is
F = 800 N
In order for it to keep moving, the force of friction (which acts horizontally in the opposite direction) must be not greater than this value. So the maximum force of friction must be
And substituting the values into eq.(1), we can find the maximum value of the coefficient of friction: