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antiseptic1488 [7]
3 years ago
9

During the expansion of a gas in piston-cylinder the relation between the pressure and the volume is given as

Physics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer: The relationship between the pressure and the volume is given as P=K/V or PV= K. (Pressure increases as Volume decreases).

Explanation:

When gas is trapped in an enclosed medium for example a cylinder by a piston. When the piston is pushed in, the gas particles will have less room to move as the VOLUME the gas occupies has been DECREASED. This will automatically lead to frequent collision of the has particles with the wall of the container. The collision exerts forces which leads to INCREASED PRESSURE.

This obeys the Boyle's law which states that the volume occupied by a fixed mass of gas is inversely proportional to the pressure, provided temperature is kept constant. This can be mathematically expressed below:

PV=K, where K is constant

P1 V1=P2 V2

Where,

P1= initial pressure

V1= initial Volume

P2= final pressure

V2= final Volume.

Therefore, increasing pressure from initial pressure to final pressure means that initial volume will change to final volume, providing the temperature remains constant.

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Why is creativity important in constructing scientific questions?
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edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
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The displacement of Edward in the westerly direction is determined as 338.32 km.

<h3>What is displacement of Edward?</h3>

The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.

The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰

The displacement is the side of the triangle facing 150⁰ = R

R² = a² + b² - 2abcosR

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2 years ago
Anna Litical analyzes the force between a planet and its moon, varying the mass of
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Answer:

Trial 1 is the largest, trial 3 is the smallest

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Given:

<em>Trial 1</em>

M₁ = 6·10²² kg

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<em>Trial  2</em>

M₂ = 6·10²² kg

d₂ = 7 000 km = 7·10⁶ м

<em>Trial  3</em>

M₃ = 3·10²² kg

d₃ = 7 000 km = 7·10⁶ м

___________

F - ?

Gravitational force:

F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m  (N)

F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m  (N)

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Trial 1 is the largest, trial 3 is the smallest

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