You are crossing the event horizon of a black hole
When you are feeling like spaghetti and you are normally only about 2 meters tall, you are now about 25 meters long, then look up over your head, you see things moving pretty quickly in the universe but that lasts only a brief instant, and then all contact with the universe is lost, you are crossing the event horizon of a black hole.
<h3>What happens when you are crossing the event horizon of a black hole?</h3>
- The point of no return is the black hole's event horizon.
- Anything that continues beyond this point will be absorbed by the black hole and disappear from the known universe forever.
- The black hole's gravity is so strong at the event horizon that it cannot be overcome or resisted by any mechanical force.
<h3>Is it possible to endure inside an event horizon?</h3>
- As a result, the individual would survive and gently float over the event horizon of the black hole without being harmed or stretched into a long, thin noodle.
<h3>What occurs beyond the horizon of the event?</h3>
- A singularity is a truly tiny point that lies beyond the event horizon where gravity is so strong that space-time itself is infinitely bent.
- The principles of physics as they exist presently break down at this point, making any hypotheses about what lies beyond mere conjecture.
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Answer:
19,551 J!
Explanation:
The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)
PE = (95)(9.8)(21)
PE = 19,551 Joules
Giant Molecular Cloud
Protostar
T-Tauri
Main Sequence
Subgiant, Red Giant, Supergiant
Core fusion
Red Giant, Supergiant
Planetary Nebula or Supernova or if they are big enough a black hole
Remnant
Wish I could help you you rock
Answer:
a) a = 6.1 m/s^2
b) a = 0.98m/s^2
Explanation:
Mass of slab = 40kg
Mass of block = 10kg
Coefficient of static friction (Us) = 0.60
Kinetic coefficient (UK) = 0.40
Horizontal force = 100N
The normal reaction from 40kg slab on 10 kg block = 10*9.81
= 98.1N
Static frictional force = Us*R
= 98.1*0.6
= 58.86N
This is less than the force applied
If 10 kg block will slide on the 40 kg slab, net force = 100 - kinetic force
Kinetic force (Uk*R) = 0.4*98.1
= 39.28N
= 39N
Net force = 100 -39
= 61N
Recall that F = ma
For 10 kg block
a = F/m
a = 61/10
a = 6.1m/s^2
b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4
= 39.24
= 39N
F = ma
a = F/m
For 40kg slab
a = 39/40
a = 0.98m/s^2
