All categories

3 years ago

When it comes to how ray lines are drawn, what makes the convex lens and concave mirror similar to each other?

Physics

1 answer:

Advocard [28]3 years ago

4 0

Answer:

Convex lens and convex mirrors are similar that

1. They have the same image characteristics at various object positions

2. They possess a positive focal length

3. Both their ray lines converge to a particular focal point

You might be interested in

A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3.0 m is initially at rest. A 20 kg boy approaches the m

nekit [7.7K]

Answer:

The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s

Explanation:

The rotational inertia of the merry-go-round = 600 kg·m²

The radius of the merry-go-round = 3.0 m

The mass of the boy = 20 kg

The speed with which the boy approaches the merry-go-round = 5.0 m/s

$F_T \cdot r = I \cdot \alpha = m \cdot r^2 \cdot \alpha$

Where;

$F_T$ = The tangential force

I = The rotational inertia

m = The mass

α = The angular acceleration

r = The radius of the merry-go-round

For the merry go round, we have;

$I_m \cdot \alpha_m = I_m \cdot \dfrac{v_m}{r \cdot t}$

$I_m$ = The rotational inertia of the merry-go-round

$\alpha _m$ = The angular acceleration of the merry-go-round

$v _m$ = The linear velocity of the merry-go-round

t = The time of motion

For the boy, we have;

$I_b \cdot \alpha_b = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Where;

$I_b$ = The rotational inertia of the boy

$\alpha _b$ = The angular acceleration of the boy

$v _b$ = The linear velocity of the boy

t = The time of motion

When the boy jumps on the merry-go-round, we have;

$I_m \cdot \dfrac{v_m}{r \cdot t} = m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t}$

Which gives;

$v_m = \dfrac{m_b \cdot r^2 \cdot \dfrac{v_b}{r \cdot t} \cdot r \cdot t}{I_m} = \dfrac{m_b \cdot r^2 \cdot v_b}{I_m}$

From which we have;

$v_m = \dfrac{20 \times 3^2 \times 5}{600} = 1.5$

The velocity of the merry-go-round, $v_m$ , after the boy hops on the merry-go-round = 1.5 m/s.

5 0

2 years ago

The part of the electromagnetic spectrum you can see is called ultraviolet light. Please select the best answer from the choices

Artyom0805 [142]

True because when the light bounces off a surface it creates a rainbow which we call roygbiv

4 0

3 years ago

George walks to a friend's house. He walks 750 meters North, then realizes he walked too far. He

MA_775_DIABLO [31]

76 meters per second

7 0

3 years ago

Read 2 more answers

A basketball is thrown up into the air. It is released with an initial velocity of 8.5 m/s. How long does it take to get to the

ehidna [41]

<h2>It takes 0.867 seconds to get to the top of its motion</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 8.5 m/s

Final velocity, v = 0 m/s - At maximum height

Time, t = ?

Acceleration , a = -9.81 m/s²

Substituting

v = u + at

0 = 8.5 + -9.81 x t

t = 0.867 s

It takes 0.867 seconds to get to the top of its motion

4 0

3 years ago

Read 2 more answers

A student pushes on a crate with a force of 100 N directed to the right. What force does the crate exert on the student?

sattari [20]

Answer:

The Force exerted on the student by crate will be 100 N.

Explanation:

As per the given Question student is trying to push the crate in right direction with the force of 100N.

And we know that, Newton's third law states that every action has equal and opposite reaction.

So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.

6 0

2 years ago