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Zielflug [23.3K]
3 years ago
9

Which item is NOT a kind of evidence used in a systematics?

Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

C. presence of "red blood"

Explanation:

ale4655 [162]3 years ago
4 0
C. Is the answer.

A term that means “a group of organisms that have similar traits and are able to produce fertile offspring” is “presence of “red blood””
An item that is not a kind of evidence used in systematics.

Cell type and common ancestry are two types used.
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A 10 kg bicycle is rolling down a hill at 5 m/s, what is its momentum?
Yakvenalex [24]

Answer:

<h2>50 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 5

We have the final answer as

<h3>50 kg.m/s</h3>

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4 0
3 years ago
A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K
Andreas93 [3]

Answer:

300 K

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Diatomic Elements
  • Moles

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • <em>P</em> is pressure
  • <em>V</em> is volume
  • <em>n</em> is moles
  • <em>R</em> is gas constant
  • <em>T</em> is temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>n</em> = 0.5 mol N₂

[Given] <em>V</em> = 6 L

[Given] <em>P</em> = 2 atm

[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] <em>T</em>

<em />

<u>Step 2: Solve for </u><em><u>T</u></em>

  1. Substitute in variables [Ideal Gas Law]:                                                          (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
  2. Multiply [Cancel out units]:                                                                               12 atm · L = (0.04105 L · atm · K⁻¹)T
  3. Isolate <em>T</em> [Cancel out units]:                                                                             292.326 K = T
  4. Rewrite:                                                                                                             T = 292.326 K

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig as our lowest.</em>

292.326 K ≈ 300 K

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