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3 years ago

What is the name of the compound with the formula ch3ch2ch2nh2? 1-propanol 1-propanamine propanal propanamide?

1 answer:

8 0

The compound is CH₃CH₂CH₂NH₂
when naming the compound the C chain has 3 C atoms and they all are in a single chain therefore alkane chain is propane.
It has a -NH₂ group attached to the C therefore functional group is 'amine'
-NH₂ is attached to a terminal C atom therefore when numbering the C atoms the C attached to the substituent should have the lowest number therefore C atom with NH₂ is carbon atom 1
therefore name of the compound is 1-propanamine

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Classify each of the following as a strong acid or a weak acid and indicate how each should be written in aqueous solution. Clas

JulijaS [17]

Answer:

HCN, weak acid

H⁺, Br⁻, strong acid

Explanation:

Hydrocyanic acid is a weak acid, according to the following equation.

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Thus, it should be written in the undissociated form (HCN).

Hydrobromic acid is a strong acid, according to the following equation.

HBr(aq) ⇒ H⁺(aq) + Br⁻(aq)

Thus, it should be written in the ionic form (H⁺, Br⁻).

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2 years ago

Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit

Rasek [7]

Answer:

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

Molarity of NaOH = 0.0811 M

Moles of NaOH = n

$0.0811 M=\frac{n}{0.0017 L}$

n = 0.0001378 mol

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.

Then 0.0001378 mol of NaOH will neutralize:

$\frac{1}{2}\times 0.0001378 mol=6.8935\times 10^{-5} mol$ of sulfuric acid.

Concentration of sulfuric acid in the acid rain sample: x

$x=\frac{6.8935\times 10^{-5}}{0.02 L}=0.0034467 mol/L$

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

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3 years ago

Remember this quote?!

muminat

Answer:

Yes

Explanation:

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2 years ago

At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oC. What will be the temperature at 1.13 atmosphere

Inessa [10]

Answer: Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$ (At constant volume and number of moles)

${P_1\times T_1}={P_2\times T_2}$

where,

$P_1$ = initial pressure of gas = 1.00 atm

$P_2$ = final pressure of gas = 1.13 atm

$T_1$ = initial temperature of gas = $100^0C=(100+273)K=373K$ K

$T_2$ = final temperature of gas = ?

${1.00\times 373}={1.13\times T_2}$

$T_2=330K$

Therefore, the final temperature of the gas will be 330 K.

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3 years ago

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IrinaVladis [17]

Answer:

The main way animal-like protists differ from plant-like protists is in the way they get energy. Animal-like protists are heterotrophs. They have to eat other protists or bacteria in order to get energy, much as animals have to eat plants or other animals to get their energy. Plant-like protists, on the other hand, are autotrophs. They can make their own energy from the sun or other sources just as plants can.

Explanation:

hope that helps ☺️

4 0

3 years ago

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