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sergiy2304 [10]
3 years ago
13

Help I'm really confused. i need this ASAP!!!!! -9a^2b^6(-7ab^-4)

Mathematics
1 answer:
Eva8 [605]3 years ago
6 0
The top of “^” needs a number to solve it.
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Rearrange the equation 5x-3y+9=0 from standard form to slope/y-intercept form.
lions [1.4K]
Y=Mx+B -> slope intercept form

The answer would be -3y=-5x-9
Divide the -3 on both sides and you get
y=5/3x+3
8 0
3 years ago
10) what is the area ratio<br> 11) what is the area of RST <br> HELP ASAP EMERGENCY
dlinn [17]

9514 1404 393

Answer:

  10)  C 4/9

  11)  B 24

Step-by-step explanation:

10) The area ratio is the square of the ratio of side lengths. The ratio of side lengths is ...

  RS/LM = 6/9 = 2/3

Then the area ratio is ...

  (2/3)² = 4/9

__

11) Using the result of question 10, the area of ∆RST is ...

  (4/9)(54 in²) = 24 in²

8 0
2 years ago
Can someone help me with #2?? it would be much appreciated! :)
jekas [21]
There you go? Is that right or no?
4 0
3 years ago
Select all of the coefficients in the expression.<br> 12xy3 + 2x5y + 4x5y2 + 7x5y.
DedPeter [7]

Answer:

The coefficients are simply 12, 2, 4, and 7.

Step-by-step explanation:

Coefficients are the numbers that come before terms. Each term has a coefficient before it.

5 0
3 years ago
Read 2 more answers
The length of the diagonal of a rectangle is √181 inches. ​ ​Which statement describes the length of the diagonal?
lakkis [162]

Answer:

The correct option is (B).

Step-by-step explanation:

The length of the diagonal of a rectangle is \sqrt{181} inches.

Compute the value of \sqrt{181} inches as follows:

The number 181 is not a square of a whole number.

So, the square root of 181 must lie between two whole numbers.

Consider the following squares:

12^{2}=144

13^{2}=169

14^{2}=196

It is quite clear that the 181 lies between the square of 13 and 14.

So, it can be said that the square root of 181 is between the square of 13 and 14.

Thus, the length of the diagonal of a rectangle is between 13 and 14 inches.

The correct option is (B).

4 0
3 years ago
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