The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
He must work additional 8 hours.
Step-by-step explanation:
Because 1550.00/20=7.75
217.00/7.75=28
28-20=8
So,an additional of 8 hours
Answer:
Both ordered pairs are solutions to this equation.
Step-by-step explanation:
If you plug in the x and y values given in the ordered pair, you make the left side of the equation equal the right for both pairs.
-3 and 4......................
