Answer:
(-6,4)
Step-by-step explanation:
If this is the system of equations here is how:
solve for 1 vairuble in the first equation, and plug that it to the other.
Answer:
1/625 or 0.0016
Step-by-step explanation:
Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
4x-11
Step-by-step explanation:
open parentheses: 4x-8-3
solve: 4x-11
