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IRINA_888 [86]
4 years ago
9

For a liquid to be useful in a thermometer, it should ?

Physics
1 answer:
Elena L [17]4 years ago
5 0

Answer:

B

Explanation:

A: The speed in which the liquid moves is irrelevant, as long as it moves.

B: This will show the temperature: expansion -> bigger number -> hotter, and vise versa. You may already know that mercury expands and contracts with the change in temperature, without changing state. That is why the first thermometers used mercury.

C: No change of state is needed in a thermometer, and may actually cause it to break.

D: Adhering to a surface will cause the liquid to be unable to move, which shouldn't happen.

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Mrs. Adams' class decides to try an experiment. She rubs a blown up balloon on Sandy's head. After this, she takes the balloon a
never [62]
A is the answer I took the test
6 0
3 years ago
Read 2 more answers
Three objects are positioned along the x axis as follows: 4.4 kg at x = + 1.1 m, 3.7 kg at x = +0.80 m, and 2.9 kg at x = +1.6 m
maxonik [38]

Answer:

the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m

Explanation:

Given that

m₁=4.4kg

x₁=+1.1m

m₂=3.7kg

x₂=+0.80m

m₃=2.9kg

x₃=+1.6m

The position of the center of mass is

         Xcm = [m₁x₁ +m₂x₂ +m₃x₃]/(m₁+m₂+m₃)

                = [(4.40kg)(1.1 m)+(3.70 kg)(0.80 m)+(2.90 kg)(1.60 m)]/(4.4 kg + 3.70 kg+2.90 kg)

              = 1.13 m

The position of the center of gravity is 1.13m

Therefore, the distance from the location of the center of gravity to the location of the center o mass for this system is 1.13m

4 0
3 years ago
An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec
jolli1 [7]

Answer:

v_o=39\ m/s\\t_m=4\ s

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

To find the initial speed we solve for vo:

\displaystyle v_o=\sqrt{2gh_m}

v_o=\sqrt{2\cdot 9.8\cdot 77.5}

v_o=39\ m/s

(b)

The maximum time or the time taken by the object to reach its highest  point is calculated as follows:

\displaystyle t_m=\frac{v_o}{g}

\displaystyle t_m=\frac{39}{9.8}

t_m=4\ s

7 0
3 years ago
Which one of the following terms is used to describe the bending of waves and subsequent spreading around obstacles or the edges
maks197457 [2]

Answer:

B)Diffraction

Explanation:

The concept of diffraction in the field of physics is defined as the deflection of a wave when it crosses an opening or hits the edge of an opaque element. Diffraction is a phenomenon that involves all waves: electromagnetic, radio, sound, etc., and it is possible to predict their behavior using different mathematical approaches. There is a method of analysis called the Huygens principle, which allows us to understand diffraction as a wavefront that is seen as a series of emitters capable of redirecting the wave when it oscillates and thus promotes propagation. Although the waves produced by the oscillators are spherical, their interference causes a flat wave that moves in the same direction as the initial one.

6 0
3 years ago
Question 7 (5 points)
Alexxx [7]

Answer:

true?

Explanation:

5 0
3 years ago
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