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3 years ago

14

What shape is the graph produced by a force vs acceleration graph?

1 answer:

Aneli [31]3 years ago

4 0

Answer:Direct students to notice the shape of the force graph (horizontal line) and acceleration graph are the same, but the velocity vs. time graph is a line with a positive slope. A constant forward force produces an increasing velocity and a constant acceleration.

Explanation:

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Somebody please help!!!

Juliette [100K]

Answer: it’s E. you can’t solve without the mass

Explanation:

3 0

3 years ago

A long solenoid that has 1 200 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00

Fantom [35]

Answer:

<h2>The current required winding is $2.65*10^-^2 mA$ </h2>

Explanation:

We can use the expression B=μ₀*n*I-------1 for the magnetic field that enters a coil and

n= N/L (number of turns per unit length)

Given data

The number of turns n= 1200 turns

length L= 0.42 m

magnetic field B= 1*10^-4 T

μ₀= $4\pi*10^-^7 T.m/A$

Applying the equation B=μ₀*n*I

I= B/μ₀*n

I= B*L/μ₀*n

$I= \frac{1*10^-^4*0.42}{4\pi*10^-^7*1.2*10^3 }$

$I= 2.65*10^-^2 mA$

8 0

4 years ago

An object of mass weighing 5.24 kilograms is raised to a height of 1.63 meters. What is the potential energy of the object at th

Nikitich [7]

PE = mgh,

Mass, m = 5.24kg, g ≈ 9.8m/s², h = 1.63m

= 5.24 * 9.8 *1.63 = 83.70376 ≈ 84

PE ≈ 84 J

5 0

3 years ago

Read 2 more answers

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

mote1985 [20]

Answer:<em> tried my best to answer your ?s:</em>

<em>B</em>

<em>A</em>

<em>B</em>

<em>D</em>

<em>A</em>

<em>A</em>

<em>B?</em>

<em>Hope this helps!!</em>

3 0

3 years ago

A quantity of N2 occupies a volume of 1.4 L at 290 K and 1.0 atm. The gas expands to a volume of 3.3 L as the result of a change

lions [1.4K]

Answer:

$\rho = 0.50 g/L$

Explanation:

As we know that

PV = nRT

here we have

$P = 1.0 atm$

$P = 1.013 \times 10^5 Pa$

so we have

$V = 1.4 \times 10^{-3} m^3$

T = 290 K

now we have

$(1.013 \times 10^5)(1.4 \times 10^{-3}) = n(8.31)(290)$

$n = 0.06$

now the mass of gas is given as

$m = n M$

$m = (0.06)(28)$

$m = 1.65 g$

now density of gas when its volume is increased to 3.3 L

so we will have

$\rho = \frac{m}{V}$

$\rho = \frac{1.65 g}{3.3 L}$

$\rho = 0.50 g/L$

5 0

3 years ago