Answer:
The work and heat transfer for this process is = 270.588 kJ
Explanation:
Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k
The Pressure-Volume relation is <em>PV</em> = <em>C</em>
<em>T = C </em> for isothermal process
Calculating for the work done in isothermal process
<em>W</em> = <em>P</em>₁<em>V</em>₁
= <em>mRT</em>₁ [∵<em>pV</em> = <em>mRT</em>]
= (5) (0.287) (272.039)
= 270.588 kJ
Since the process is isothermal, Internal energy change is zero
Δ<em>U</em> =
From 1st law of thermodynamics
Q = Δ<em>U </em>+ <em>W</em>
= 0 + 270.588
= 270.588 kJ
(2.0 x 10² N/Coul) x (-1.6 x 10⁻¹⁹ Coul) = -3.2 x 10⁻¹⁷ N
The magnitude is 3.2 x 10⁻¹⁷ Newton.
Answer:
Value of each resistor will be 3 ohm
Explanation:
It is given that three are connected to a 12 volt battery in parallel
As we know that voltage across parallel combination is same
So voltage across each resistor will be same as 12 volt
It s given that current across each resistor is amperes
From coulomb's law we know that voltage across any resistor is equal to
V = I R
So resistance will be equal to
So value of each resistor will be 3 ohm