Answer:
8.85
Explanation:
The computation of the charge that must place on them in order to create 1000 N/C field between the plates is shown below:
We know that
E = (Q/A) ÷ E_o
1000 = Q ÷ 0.01×8.85× 10^-12
Q = 8.85 × 10^-12
So,
The answer is 8.85
The above formula should be applied so that the correct value could come
And, the same would be relevant
Answer:
The answer is 631.157
Explanation:
The question requested that the answer to the subtraction of 26.543 from 657.70 must be written using significant figures.
Here are a few tips about how to Identify significant figures.
1) It should be noted that <u>the number "0" is what is usually (but not always) affected</u> while trying to identify significant figures. Hence, <u>all other numbers/digits are always significant</u>. For example, 26.543 has five significant figures.
2) The zeros found between these "other numbers/digits" are also significant. For example, 2202 has four significant figures.
3) In the case of a decimal, the tailing zeros or the final zero is also significant. 657.70 and 657.07 have five significant figures.
Now, back to the question
657.70 - 26.543 = 631.157.
Our final answer does not have a zero, hence all the digits (six) are significant.
Answer:
15 m/s to the right
Explanation:
Let's say right is positive and left is negative.
Momentum is conserved:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(6.0 kg) (25.0 m/s) + (15 kg) (0 m/s) = (6.0 kg) (-12.5 m/s) + (15 kg) v₂
v₂ = 15 m/s
1 kg = 1,000 grams
To get 75kg in units of grams, we just multiply 75 by 1,000
75* 1,000 = 75,000 grams
Answer:
F ’= 1/32 F
We see that the value of the force is the initial force over 32
Explanation:
In this problem the sphere that is touching the others is connected to ground, after each touch,
Let's analyze the charge of the gray sphere, when you touch it for the first time, the charge is divided between the two spheres each having Q / 2, when the sphere separates and touches ground, its charge passes zero. When I touch the gray dial again, its charge is reduced by half
½ (Q / 2) = ¼ Q
For the red dial repeat the same scheme
with the first touch the charge is reduced to Q / 2
with the second touch e reduce to ½ (Q / 2) = ¼ Q
with the third toce it is reduced to ½ (¼ Q) = ⅛ Q
Now let's analyze what happens to the electric force
if the force is F for when the charge of each sphere is Q
F = k Q Q / r²
with the remaining charge strength is
F ’= k (¼ Q) (⅛ Q) / r²
F ’= 1/32 k Q Q / r²
F ’= 1/32 F
We see that the value of the force is the initial force over 32
