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3 years ago

Which is an example of a mixture?

Physics

2 answers:

fgiga [73]3 years ago

7 0

The answer is: B. Trail Mix

Lena [83]3 years ago

7 0

Answer:

B. Trail Mix

Explanation:

There are different kinds of nuts, seeds, etc. This is a mixture

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Why did Archimedes shout eureka what did he find out?

Natalka [10]

Answer:

I believe he shouted eureka after he stepped into a bath and noticed that the water rose. He then realized that the volume of water displaced must be equal to the volume of the part of his body he had submerged

Explanation:

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3 years ago

The _____ of an object consists of its speed and direction.

ELEN [110]

Velocity would be an answer

3 0

3 years ago

A typical rechargeable deep-cycle battery for an electric trolling motor (fishing boat) delivers 10A of current at a voltage of

Oksi-84 [34.3K]

Answer:

a) 360 kQ

b) 4.32 MJ

c) 1200 W-h

Explanation:

a) The definition of the current is.

$I= \frac{Q}{t}$

having a count that 10 hours = 36.000 s

$Q = I*t$

$Q = 36000*10 = 360.000 [Q]$

b) The definition of the Energy in power terms is.

$E = \int\limits^{t}_{0} {P} \, dt$

and the definition of power is:

$P = V*I = 12 * 10 = 120 [W]$

replacing in the energy formula.

$E = \int\limits^{36.000}_{0} {120} \, dt$

solving the integral, have into account that t is in seconds.

$E=P*t=120*36000=4.320.000=4.32 [MJ]$

c) The energy in W-h, we can find it multiplying power by hours

$E = P*t =120*10 = 1200 W-h$ .

3 0

3 years ago

20 PTS!

klemol [59]

its acceleration is zeo

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

8 0

3 years ago

Read 2 more answers

A proton is released in a uniform electric field, and it experiences an electric force of 2.04×10−14 N toward the south.

Lemur [1.5K]

Answer:

Part A:

$E=127500N/C\\E=1.275*10^{5} N/C$

Part B:

Option B (Towards the South)

Explanation:

Part A:

Magnitude if electric field E:

E=Force/charge

Force=2.04×10−14 N

Charge=1.6×10−19 C

$E=\frac{2.04*10^{-14}}{1.6*10^{-19}} \\E=127500N/C\\E=1.275*10^{5} N/C$

Part B:

Option B (Towards the South)

As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.

7 0

4 years ago