A billiard ball collides with a stationary identical billiard ball to make it move. If the collision is perfectly elastic, the first ball comes to rest after collision.
<h3>Why does the first ball comes to rest after collision ?</h3>
Let m be the mass of the two identical balls.
u1 = velocity before the collision of ball 1
u2 = 0 = velocity of second ball that is at rest
v1 and v2 are the velocities of the balls after the collision.
From the conservation of momentum,
∴ mu1 + mu2 = mv1 + mv2
∴ mu1 = mv1 + mv2
∴ u1 = v1 + v2
In an elastic collision, the kinetic energy of the system before and after collision remains same.

∴ 
∴ 
∴
₁
₂ = 0
- It is impossible for the mass to be zero.
- Because the second ball moves, velocity v2 cannot be zero.
- As a result, the velocity of the first ball, v1, is zero, indicating that it comes to rest after collision.
<h3>What is collision ?</h3>
An elastic collision is a collision between two bodies in which the total kinetic energy of the two bodies remains constant. There is no net transfer of kinetic energy into other forms such as heat, noise, or potential energy in an ideal, fully elastic collision.
Can learn more about elastic collision from brainly.com/question/12644900
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Answer:
400000
Explanation:
So first solve one part:
(3.25 * 10^5)
(3.25 * 100,000)
= 325000
Then solve the next part:
(7.5 * 10^4)
(7.5 * 10000)
= 75000
Now lastly, add the two answers:
325000 + 75000 = 400000
Therefore,
(3.25 x 10^5) + (7.5 x 10^4) = 400000
48 degrees Farenheit, as 0 degrees Celsius is equivalent to 32 degrees Farenheit.
Answer:
The graph with a more steeper slope
Explanation:
If the x axis represented time and the y axis represented speed the steeper the slope the more faster something was moving in a shorter amount of time. On the other hand a less steeper slope means an object is gradually picking up speed in a longer amount of time thus makeing it slower
HOPE THIS HELPED:)