3 years ago

Will give brainliest to right answer!

Physics

1 answer:

viva [34]3 years ago

8 0

The correct answer is D.

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A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a

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Answer:

The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus $S = 1\times10^{9}\ N/m^2$

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

$S=\dfrac{Fl_{0}}{A\Delta x}$

$\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}$

$\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}$

Put the value into the formula

$\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}$

$\Delta x=3.34\times10^{-6}\ m$

Hence, The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

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