Answer:
C
Step-by-step explanation:
In a Pythagorean triple the square on the longest side is equal to the sum of the squares on the other 2 sides.
A
longest side = 10 ⇒ 10² = 100
6² + 8² = 36 + 64 = 100
A is a Pythagorean triple
B
longest side = 17 ⇒ 17² = 289
8² + 15² = 64 + 225 = 289
B is a Pythagorean triple
C
longest side = 9 ⇒ 9² = 81
5² + 8² = 25 + 64 = 89
89 ≠ 81
C is not a Pythagorean triple
D
longest side = 13 ⇒ 13² = 169
5² + 12² = 25 + 144 = 169
D is a Pythagorean triple
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
4x=(-3x)+18
7x=18
x≈2.5
4(2.5)=3y-2
10=3y-2
12=3y
y=4
your answer is B.(2.5,4)
Hello :
<span>F(x)=4x-1 and g(x)=2x²+3.
</span><span>f(x) + g(x) = 2x²+4x+2
</span><span> the domain oh : f+g is : R</span>