Question

Graph a parabola whose vertex is at (3,5) with y- intercept at y=1

Answer 1

Answer:

  see the attachment

Step-by-step explanation:

The vertex form of the equation of a parabola is ...

  y = a(x -h)^2 +k . . . . . . vertical scale factor "a", vertex (h, k)

For the given points, we have ...

  1 = a(0 -3)^2 +5

  -4 = 9a . . . . . . subtract 5 and simplify

  -4/9 = a

So, the equation of the parabola is ...

  y = (-4/9)(x -3)^2 +5

Its graph is shown below.