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Archy [21]
3 years ago
15

You have a 81.9 81.9 mF capacitor initially charged to a potential difference of 11.1 11.1 V. You discharge the capacitor throug

h a 3.19 3.19 Ω resistor. What is the time constant?
Physics
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

The time constant is 0.26 s

Explanation:

From ohm's law,

Current (I) = potential difference ÷ resistance = 11.1 ÷ 3.19 = 3.48 A

Quantity of electricity (Q) = capacitance × potential difference = 81.9×10×^-3 × 11.1 = 0.90909 C

time constant (t) = Q/I = 0.90909/3.48 = 0.26 s

lukranit [14]3 years ago
8 0
<h2>Answer:</h2>

0.261s

<h2>Explanation:</h2>

For an R-C discharging circuit, the time constant τ, is the product of the capacitance (C) of the capacitor and the resistance (R) of the resistor. i.e

τ = R x C               ------------------(i)

From the question;

R = 3.19Ω

C = 81.9mF =  81.9 x 10⁻³F

Substitute these values into equation (i) as follows;

τ = 81.9 x 10⁻³ x 3.19

τ = 261.261 x 10⁻³

τ = 0.261s

Therefore, the time constant is 0.261s

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3 years ago
What term was used to describe the final digit
xxMikexx [17]

Answer:

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7 0
2 years ago
What is the temperature of a 3.72 mm cube (e=0.288) that radiates 56.6 W?
blsea [12.9K]

Answer:

The temperature is 2541.799 K

Explanation:

The formula for black body radiation is given by the relation;

Q = eσAT⁴

Where:

Q = Rate of heat transfer 56.6

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A = Surface area of the cube = 6×(3.72 mm)² = 8.3 × 10⁻⁵ m²

e = emissivity = 0.288

T = Temperature

Therefore, we have;

T⁴ = Q/(e×σ×A) = 56.6/(5.67 × 10⁻⁸ × 8.3 × 10⁻⁵ × 0.288) = 4.174 × 10¹⁴ K⁴

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7 0
3 years ago
Assuming that each nucleus is roughlyspherical and that its mass is roughly equal to A (in atomic mass units {\rm u}), what is t
lara [203]

Answer:

ρ/ρ2 = 3 / R₀       the two densities are different

Explanation:

Density is defined as

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As the nucleus is spherical

       V = 4/3 π r³

Let's replace

      ρ = A / (4/3 π R₀³)

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b)

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Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

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In this case it does not say that the nucleon number is A (F = A), the relationship is

     ρ/ρ2 = 3 / R₀

I see that the two densities are different

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Answer:

is 3 and 2

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