4.0km at 25 west of south, then 2.0km at 15 north east

A pendulum consists of a 2.7 kg stone swinging on a 4.0 m string of negligible mass. The stone has a speed of 8.1 m/s when it pa

Brut [27]

Answer:

a). v=4.77 $\frac{m}{s}$

b). β=80.61

c). E=88.5J

Explanation:

a).

$m1=2.7 kg\\L=4m\\v_{1}=8.1 \frac{m}{s}\\\beta=63$

$\frac{m*v_{1} ^{2} }{2}+m*g*y_{1}=\frac{m*v_{2}^{2} }{2}+m*g*y_{2}\\\frac{m*v_{1} ^{2} }{2}=\frac{m*v_{2}^{2} }{2}+m*g*y_{2}\\v_{2}=\sqrt{v_{1}^{2}-2*g*y_{2}}\\y_{2} =L-L*cos(\beta)\\v_{2}=\sqrt{v_{1}^{2}-2*g*(L-L*cos(\beta))}\\v_{2}=\sqrt{8.1^{2}-2*9.8*(4(1-*cos(63))}\\v_{2}=\sqrt{8.1^{2}-42.8}\\v_{2}=\sqrt{64-42.8}\\v_{2}=\sqrt{21.19}=4.77 \frac{m}{s}$

b).

$\frac{m*v_{1}^{2}}{2} +m*y_{1} =\frac{m*v_{2}^{2}}{2} +m*y_{2}\\\frac{m*v_{1}^{2}}{2} +0 =0 +m*y_{2}\\y_{2}=\frac{v_{1}^{2}}{2*g}=\frac{(8.1^\frac{m}{s}){2}}{2*9.8\frac{m}{s^{2} }}=3.34 m\\ 3.34m=L(1-cos(\alpha)\\3.34m=4*(1-cos(\alpha ))\\cos(\alpha )=\frac{4-3.34}{4}=0.16\\(\alpha )= cos^{-1}*(0.163)\\ (\alpha )= 80.61$

c).

$E=\frac{m*v_{1} ^{2} }{2}\\ E=\frac{(2.7kg)*(8.1\frac{m}{s})^{2}}{2}=\frac{177.147\frac{kg*m^{2}}{s^{2}}}{2}\\\\E=88.5 J$

6 0

3 years ago

The shortest wavelengths that we can see are experienced as what colors?

astra-53 [7]

If you think about the colors of the rainbow red, orange, yellow, green, blue, indigo, and violet. That list of colors shows you the spectrum of visible light and the further right (towards violet) you go the more energy the waves have while the more left (towards red) you go the less energy the waves have. wavelength and energy are inversely proportional meaning that as energy goes up, wavelength goes down. therefore the more right (towards violet) you move in the spectrum, the smaller the wavelengths get.

6 0

3 years ago

Safety belts and occupant protection systems are installed to reduce the harmful effects of the force of _____ during a collisio

Phantasy [73]

To lessen the negative impacts of the force generated during a collision, safety belts and occupant protective relays are installed.

Importance of safety belts:

The purpose of a seat belt usually referred to as a safety belt or a safety belt, is to protect the driver or an occupant of a vehicle from a potentially dangerous movement that may occur during an accident or an abrupt stop. By minimizing the power of secondary hits with interior striking hazards, maintaining proper occupant positioning for the airbag, and preventing people from being expelled from the vehicle after an accident or if the automobile rolls over, seat belts help minimize the chance of a fatal accident in traffic collisions. When the car is moving, the passenger and the driver move together with it at the same pace.

The occupants continue moving at the same pace the vehicle was traveling at when it stopped if it unexpectedly stops or crashes. To stop the driver and other passengers from exiting the vehicle or contacting the interiors of the vehicle, seatbelts apply an equal and opposite force to them. Due to their crucial function in occupant safety, seatbelts are regarded as the main restraint devices.

Learn more about safety belts here:

brainly.com/question/5626690

#SPJ4

3 0

1 year ago

Atmospheric pressure at the top of mount everest.

Mumz [18]

Answer:

Mt. Everest (elevation of 8848 m), the air pressure is 253 mmHg. The summit of Mt. Everest, the highest elevation on earth, where the pressure averages around 300 mb." As altitude increases, the air becomes thinner, the density of air decreases, and the pressure of the air decreases as wel

6 0

3 years ago

An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucle

shtirl [24]

Answer:

$-9.45\times10^{-16} \text{ J}$

Explanation:

According to Coulomb's law, the force of attraction between two point charges, $q_1$ and $q_2$ , separated by a distance $d$ is given by

$F = k\dfrac{q_1q_2}{d^2}$

$k$ is a constant with a value of $9\times10^9\text{ F/m}$ .

When we substitute the values from the question,

$F = (9\times10^9\text{ F/m})\dfrac{(-1.60\times10^{-19} \text{ C})\times(+1.31\times10^{-17}\text{ C})}{(1.00\times10^{-10}\text{ m})^2} = -1.89\times10^{-6} \text{ N}$

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

$W = F\times r$

$W = (-1.89\times 10^{-6} \text{ N})\times(5.00\times10^{-10}\text{ m}) = -9.45\times10^{-16} \text{ J}$

This is negative because work is done on the electron, not by it.

3 0

3 years ago