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scZoUnD [109]
3 years ago
14

Which option describes energy being released as heat?

Chemistry
1 answer:
Elza [17]3 years ago
3 0

Answer:

a

Explanation:

A child shivering gives off energy to transfer that energy into heat

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The diagram below shows the different phase transitions that occur in matter.
Nimfa-mama [501]

The arrow that represents the transition in which dew is formed would be arrow 4.

<h3>How is dew formed?</h3>

Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.

From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.

Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.

More on dew formation can be found here: brainly.com/question/23169635

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3 0
2 years ago
Read 2 more answers
If two gases a and b in separate 1 liter containers
Anton [14]

The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

<h3>What is pressure?</h3>

Pressure is the force exerted by any object on another object.

Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.

When both gases a and b exert together, the pressure then

2 atm + 3 atm = 5 atm.

Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

Learn more about pressure

brainly.com/question/12977546

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7 0
2 years ago
A sample of gas has an initial volume of 3.00 L and an initial pressure of 2.14 atm. If the volume expands to 8.15 L, what is th
Alla [95]

Answer:

The final pressure is 0.788 atm (option b).

Explanation:

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:

P*V=k

Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1*V1=P2*V2

In this case:

  • P1= 2.14 atm
  • V1= 3 L
  • P2= ?
  • V2= 8.15 L

Replacing:

2.14 atm*3 L= P2* 8.15 L

Solving:

\frac{2.14 atm*3 L}{8.15 L} =P2

0.788 atm= P2

<u><em>The final pressure is 0.788 atm (option b).</em></u>

6 0
3 years ago
A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne
Ymorist [56]

Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

P = 5.7 × 10⁻³ atm

Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

mHe = 0.52 mg = 0.52 × 10⁻³ g

mNe = 2.05 mg = 2.05 × 10⁻³ g

The molar mass of He is 4.00 g/mol. The moles of He are:

0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K

P = 2.5 × 10⁻³ atm

The total pressure is the sum of the partial pressures.

P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm

6 0
3 years ago
Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h
aleksandrvk [35]

Answer:

Concentration = 1.32 m

Boiling point = 83.44^{0}C

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

elevationinboiling point=K_{b}Xmolality

i) For benzene

T-80.1=2.53Xm

T=2.53m+80.1 ....(1)

ii) For carbon tetrachloride

T-76.8=5.03Xm

T=5.03Xm+76.8 ...(2)

Equating the two equations:

5.03Xm+76.8=2.53m+80.1\\m=1.32molal

Putting value of "m" in equation "1"

T=2.53(1.32)+80.1=83.44^{0}C

5 0
3 years ago
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