The arrow that represents the transition in which dew is formed would be arrow 4.
<h3>How is dew formed?</h3>
Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.
From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.
Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.
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The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.
<h3>What is pressure?</h3>
Pressure is the force exerted by any object on another object.
Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.
When both gases a and b exert together, the pressure then
2 atm + 3 atm = 5 atm.
Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.
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Answer:
The final pressure is 0.788 atm (option b).
Explanation:
Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:
P*V=k
Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1*V1=P2*V2
In this case:
- P1= 2.14 atm
- V1= 3 L
- P2= ?
- V2= 8.15 L
Replacing:
2.14 atm*3 L= P2* 8.15 L
Solving:
0.788 atm= P2
<u><em>The final pressure is 0.788 atm (option b).</em></u>
Answer:
pHe = 3.2 × 10⁻³ atm
pNe = 2.5 × 10⁻³ atm
P = 5.7 × 10⁻³ atm
Explanation:
Given data
Volume = 1.00 L
Temperature = 25°C + 273 = 298 K
mHe = 0.52 mg = 0.52 × 10⁻³ g
mNe = 2.05 mg = 2.05 × 10⁻³ g
The molar mass of He is 4.00 g/mol. The moles of He are:
0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol
We can find the partial pressure of He using the ideal gas equation.
P × V = n × R × T
P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K
P = 3.2 × 10⁻³ atm
The molar mass of Ne is 20.18 g/mol. The moles of Ne are:
2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol
We can find the partial pressure of Ne using the ideal gas equation.
P × V = n × R × T
P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K
P = 2.5 × 10⁻³ atm
The total pressure is the sum of the partial pressures.
P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm
Answer:
Concentration = 1.32 m
Boiling point = 
Explanation:
Let the boiling point of two solutions = T
Let the molal concentration of the two solutions= m
The relation between elevation in boiling point and molal concentration is:
i) For benzene
....(1)
ii) For carbon tetrachloride
...(2)
Equating the two equations:
Putting value of "m" in equation "1"
