The rate law for 2 NO2 +F2⇔ 2NO2 F is
rate = k[ NO2][F2]
<h3>explanation</h3>
The order with respect to reactant is the exponent is raised in the rate law. Since the reaction above is a second order overall and is a first order in F2 then it must be also a first order in NO2 therefore the rate raw = K[No2][F2]
Explanation:
<u>Moles is denoted by given mass divided by the molecular mass , </u>
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
For example ,
For a compound X ,
The given mass i.e. w = 20 g
and the molecular mass ,i.e. , m = 10 g / mol
Then the moles can easily be calculated by using the above formula ,
n = w / m
n = 20 g / 10 g/mol = 2 mol
Hence , answer = 2 mol.