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Olenka [21]
3 years ago
13

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h

as carbon tetrachloride as the solvent. Determine that molal concentration, m (or b), and boiling point, Tb.
benzene boiling point=80.1 Kb=2.53

carbon tetrachloride boiling point=76.8 Kb=5.03
Chemistry
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

Concentration = 1.32 m

Boiling point = 83.44^{0}C

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

elevationinboiling point=K_{b}Xmolality

i) For benzene

T-80.1=2.53Xm

T=2.53m+80.1 ....(1)

ii) For carbon tetrachloride

T-76.8=5.03Xm

T=5.03Xm+76.8 ...(2)

Equating the two equations:

5.03Xm+76.8=2.53m+80.1\\m=1.32molal

Putting value of "m" in equation "1"

T=2.53(1.32)+80.1=83.44^{0}C

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