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1 year ago

The diagram below shows the different phase transitions that occur in matter.

Chemistry

2 answers:

IRISSAK [1]1 year ago

4 0

Answer:

Arrow 4

Explanation:

Nimfa-mama [501]1 year ago

3 0

The arrow that represents the transition in which dew is formed would be arrow 4.

<h3>How is dew formed?</h3>

Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.

From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.

Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.

More on dew formation can be found here: brainly.com/question/23169635

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Explain the term "amphoteric"

Natali5045456 [20]

A substance either an ion or a molecule that can act either an acid or a base depending on a medium is called Amphoteric. Some metals like zinc, tin, copper and aluminium which produce either metal oxides or hydroxides are examples of amphoteric. During the Amphoterism, the metal compound acts either an acid or a base depending on their oxidation state.

4 0

3 years ago

Can someone please help me answer these questions and I’ll give you brainlest!!!!!

pickupchik [31]

Explanation:

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5 0

2 years ago

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

7 0

3 years ago

10) Give two example of where you would find elements in our daily lives.

Phoenix [80]

Carbon is found in oil and gas.
Aluminum a light metal used in making pots and pans.
Bromine is used in photography.

6 0

3 years ago

Which of the following electromagnetic waves are listed in the correct order from longest wavelength to shortest wavelength

Ghella [55]

Good afternoon,

Infrared light wavelengths = 1,000 nm - 750 nm

Visible light wavelengths = 750 nm - 400 nm

UV (Ultraviolet) light wavelengths = 400 nm - 10nm

So, the correct order is Infrared - Visible - Ultraviolet

I hope this has satisfied you, and if you need anymore help, feel free to ask.

Have a good afternoon!

8 0

3 years ago