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1 year ago

The diagram below shows the different phase transitions that occur in matter.

Chemistry

2 answers:

IRISSAK [1]1 year ago

4 0

Answer:

Arrow 4

Explanation:

Nimfa-mama [501]1 year ago

3 0

The arrow that represents the transition in which dew is formed would be arrow 4.

<h3>How is dew formed?</h3>

Dew is formed by condensation. Condensation, in itself, involves a transition from a gas phase to a liquid phase.

From the diagram, the arrow that represents a transition from gas to liquid is arrow 4.

Thus, the arrow that represents the transition that leads to the formation of dew would be arrow 4.

More on dew formation can be found here: brainly.com/question/23169635

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Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1

Drupady [299]

Answer : The value of second ionization energy of Ca is 1010 kJ.

Explanation :

The formation of calcium oxide is,

$Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)$

$\Delta H_f^o$ = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of $CaO$ :

(1) Conversion of solid calcium into gaseous calcium atoms.

$Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)$

$\Delta H_s$ = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

$Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)$

$\Delta H_I_1$ = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

$Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)$

$\Delta H_I_2$ = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

$O_2(g)\overset{\Delta H_D}\rightarrow OI(g)$

$\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)$

$\Delta H_D$ = dissociation energy of oxygen = $\frac{498}{2}=249kJ$

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

$O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)$

$\Delta H_E_1$ = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

$O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)$

$\Delta H_E_2$ = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

$Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)$

$\Delta H_L$ = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

$\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L$

Now put all the given values in this equation, we get:

$-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)$

$\Delta H_I_2=1010kJ$

Therefore, the value of second ionization energy of Ca is 1010 kJ.

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3 years ago

Answer in two or three sentences

Mama L [17]

Answer:

<em>Knowing how elements and compounds react together is essential in everyday life is essential to people like a scientist and someday you might become a scientist no matter what you become you will have to learn all that you can.</em>

UwU Hope I helped

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3 years ago

Covalent bonds are formed between _______.

damaskus [11]

Covalent bonds are formed between nonmetals.

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3 years ago

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Convert 0.000371 into scientific notation

Svetach [21]

First look at the numbers. Notice that this is in decimal form. When it's in decimal form, you have to move the decimal to the right until you see a different number other than 0. Therefore, starting with decimal, move it to the right 4 times since a # bigger than 0 is there. 0.000371 - - - - The answer will be 3.71^-4 If it is in decimal form, the power will be a negative

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3 years ago

In order to maintain a sodium chloride (NaCl) concentration similar to ocean water, an aquarium must contain 4.7 g NaCl per 100

yawa3891 [41]

Answer:

0.047

Explanation:

mass percent is part/whole mass

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2 years ago