All categories

3 years ago

H(x)=-2x-5, find h(-2)

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

h(-2) = -1

Step-by-step explanation:

h(x)=-2x-5

Let x= -2

h(-2)=-2*-2-5

= 4 -5

h(-2) = -1

You might be interested in

Jamie went to the his 6 friends. For each friend, he spent $4.75 for a sandwich, $1.25 for a cold beverage, and $.56 for a piece

masha68 [24]

Answer:

Jamie spent $39.36 in total.

Step-by-step explanation:

First, add the money spent for the sandwich, beverage, and fruit together.

4.75 + 1.25 + .56 = 6.56

Then, multiply the amount spent for one friend by six to find the total.

6.56 x 6 =39.36

I hope this helped you!

8 0

3 years ago

Find the values of x and y.

vova2212 [387]

Look at the picture.

We have the equation (1) 12x + 4y = 40.

We know, the sum of the acute angles in a right triangle is 90°.

Therefore we have the equation (2) (12x + 4y) + (17x - y) = 90

Substitute (1) to (2):

40 + 17x - y = 90 subtract 40 from both sides

17x - y = 50 (3)

We have the system of equations:

$\left\{\begin{array}{ccc}12x + 4y = 40&|:4\\17x-y=50\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x + y = 10\\17x-y=50\end{array}\right}\ \text{add both side of equations}\\.\qquad20x=60\qquad|:20\\.\qquad x=3$

Substitute the value of x to (3)

$17(3)-y=50\\51-y=50\qquad|-51\\-y=-1\to y=1$

Answer: x = 3 and y = 1.

4 0

3 years ago

The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordina

valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

$M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

$(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5$