(a^2)^4 = a^8, and (b^3)^4 = b^12. Thus, the quotient is
a^8
--------
b^12
There are 6 possibilities.
Rhino, elephant, lion
rhino, lion, elephant
elephant, lion, rhino
elephant, rhino, lion
Lion, rhino, elephant
lion, elephant, rhino
The answer is 35 i think but i am not sure
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability of the television passing the test is p = 0.95
The sample size is n = 10
Generally the comprehensive testing process for all essential functions follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%7B0.95%7D%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B10%20%2A%20%200.6302%20%20%2A%200.05%20%5D%2B%20%5B1%20%2A0.5987%20%2A%201%20%5D%20)
=> 
To compare the two classes, the Coefficient of Variation (COV) can be used.
The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.