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Maurinko [17]
3 years ago
11

H(x)=-2x-5, find h(-2)

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

h(-2) = -1

Step-by-step explanation:

h(x)=-2x-5

Let x= -2

h(-2)=-2*-2-5

      = 4 -5

h(-2) = -1

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 a^8
--------
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3 0
3 years ago
Solve the equation<br><br> (-7) (-5)
Tanzania [10]
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6 0
3 years ago
A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t
Scorpion4ik [409]

Answer:

The probability is   P(X \le 9) =0.9138

Step-by-step explanation:

From the question we are told that

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Generally the comprehensive testing process for all essential functions  follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators      

    Generally the probability that at least 9 pass the test is mathematically represented as

     P(X \le 9) =  P(X = 9) + P(X = 10 )

=>  P(X \le 9) = [^{10}C_9 *  (0.95)^9 *  (1- 0.95)^{10-9}]+ [^{10}C_{10} *  {0.95}^{10} *  (1- 0.95)^{10-10}]

=> P(X \le 9) = [10 *  0.6302  * 0.05 ]+ [1 *0.5987 * 1 ]

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8 0
3 years ago
There are two calculus classes at your school classes have a class average of 75.5 the first class as a standard deviation of 10
DENIUS [597]
To compare the two classes, the Coefficient of Variation (COV) can be used.

The formula for COV is this:
C = s / x

where s is the standard deviation and x is the mean

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For the second class:
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The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
8 0
3 years ago
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