Answer:
we need an out of sorry -_-
I don't think that's possible.
So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)
</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
