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3 years ago

Graph the inequality.

leqslant 2" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

grigory [225]3 years ago

4 0

Plot a shaded point (closed circle) on (0,2) then shade above the line. the line should be horizontal or parallel to the x axis

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Which describes the<br> correlation shown in the scatterplot? help pls

Yuri [45]

Answer:

Step-by-step explanation:

There is a negative correlation. The direction of a line if we plot it generally through thi scatter plot would be going down, negative.

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3 years ago

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What is the equation of the line that passes through the point (- 1, 5) and is parallel to the line y = - 3x + 5

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

Parallel lines has the same slope.

The equation of a line that passing through point (x₁, y₁) with a slope of m is:

y - y₁ = m(x - x₁)

m = -3

(-1, 5) ⇒ x₁ = -1, y₁ = 5

Therefore the equation:

y - 5 = -3(x + 1)

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3 years ago

5. Skylar got a manicure for $25. If she plans to<br> tip 20%, how much is her tip?

Harman [31]

Answer:

$5.00

Step-by-step explanation:

All we have to do is multiply 25 x 1/5 or 20%

25 x 1/5 = $5.00

to check, $5 x 5 = 25

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3 years ago

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From 1st principle find the derivative of log (ax+b)

OLga [1]

Answer:

Step-by-step explanation:

The parent function here is y = log x, where 10 is the base.

The derivative of y = log x is dy/dx = (ln x) / ln 10.

The derivative of y = log (ax+b) is found in that manner, but additional steps are necessary: differentiate the argument ax + b:

The derivative with respect to 10 of log (ax + b) is:

dy/dx = [ 1 / (ax + b) ] / [ ln 10 ] *a, where a is the derivative of (ax + b).

Alternatively, we could express the answer as

dy/dx = [ a / (ax + b) ] / [ ln 10 ]

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3 years ago

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago