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4 years ago

There is 2 questions both need work shown

Mathematics

1 answer:

DaniilM [7]4 years ago

6 0

Answer:

1.) 46.66 (MANY SIXES) 2.) 4180.5

Step-by-step explanation:

WELL. Its easy, you just need to divide the work.

1) 13.82 /0.3

=46.066667

2.) 863.1/0.2

=4180.5

Hope this helps ;)

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If 3/5 of the certain length is 210m then 5/7 of length is

Mamont248 [21]

Answer:

250 m

Step-by-step explanation:

Let the total length be x m.

$\therefore \: \frac{3}{5} \times x = 210 \\ x = 210 \times \frac{5}{3} \\ x = 70 \times 5 \\ x = 350 \: m \\ \\ \frac{5}{7} \times x = \frac{5}{7} \times 350 = 5 \times 50 = 250 \: m$

4 0

3 years ago

Read 2 more answers

In university A, the number of graduate students was approximately 25 comma 000 fewer than the number of undergraduate students

alekssr [168]

Answer:

The number of graduate students attend university A is $G=n-25,000$

Step-by-step explanation:

Consider the provided information.

We need to determine how many graduate students attend university A?

The number of undergraduate students was n.

The number of graduate students was approximately 25,000 fewer than the number of undergraduate students.

Let G represents the number of graduate student.

$G=n-25,000$

Hence, the number of graduate students attend university A is $G=n-25,000$

4 0

3 years ago

In ΔXYZ, XY = 6.32, YZ = 5.83, and XZ = 11.05. m∠Y = º.

Dominik [7]

Answer: 130.8 degrees

Explanation:

The problem can be solved by using the cosine theorem:

$a^2 = b^2 + c^2 - 2bc cos \alpha$ (1)

where

a,b,c are the lengths of the three sides of the triangle

$\alpha$ is the angle between b and c

In this problem, we can identify a,b,c, with:

a = XZ = 11.05

b = XY = 6.32

c = YZ = 5.83

So, the angle $\alpha$ corresponds to the angle m∠Y. Re-arranging eq.(1), we find

$cos \alpha = \frac{b^2+c^2-a^2}{bc}=\frac{(6.32)^2+(5.83)^2-(11.05)^2}{2(5.83)(6.32)}=-0.654$

So, the angle is

$\alpha=cos^{-1}(-0.654)=130.8^{\circ}$

3 0

4 years ago

Read 2 more answers

Wha the MIDPOINT of (-6, 8) and (6, -7)

Serhud [2]

The midpoint is (0, 1/2)
hope this helps

8 0

3 years ago

Read 2 more answers

3. Suppose m = 2 + 6i, and |m+n|=3√10, where n is a complex number.

Anestetic [448]

Answer:

Step-by-step explanation:

Suppose m = 2 + 6i, and |m+n|=3√10,

The modulus sign means m+n can either be positive or negative as shown.

If it is positive:.2+6i+n = 3√10

n = 3√10-(2+6i)

n = 3√10-2-18√10i

n = (-2+3√10)+√10i

b) Example of the complex number is given as (-2+3√10)+√10i. This is a complex number because it contains the real part and the imaginary part.

7 0

3 years ago