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3 years ago

There is 2 questions both need work shown

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

1.) 46.66 (MANY SIXES) 2.) 4180.5

Step-by-step explanation:

WELL. Its easy, you just need to divide the work.

1) 13.82 /0.3

=46.066667

2.) 863.1/0.2

=4180.5

Hope this helps ;)

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Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses to from which to choose. (a) Ini

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Answer:

So the number of total combinations is 35.

Step-by-step explanation:

We know that Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses.

Therefore, she have total 7 courses.

So, we calculate the number of combinations to choose 4 out of 7 courses.

We get:

$C_4^7=\frac{7!}{4!(7-4)!}=35\\$

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Evgesh-ka [11]

Properties of Logs

logb(x/y) = logbx - logby.

therefore

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Solve log 5 (4) and log 5 (7) with the base change of the logarithm

log 5 4 = log 4 / log 5

Use the calculator:

log 5 4 =0.8613531161

log 5 7 = log 7 / log 5

log 5 7 =1.2090619551

log5 (4/7)= log5 (4)- log5 (7)=-0.347708839

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