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2 years ago

A line passes through the point (9. -9) and has a slope of -4/3.

Mathematics

1 answer:

professor190 [17]2 years ago

6 0

Answer:

$y = \frac{ - 4}{3} x + 3$

Step-by-step explanation:

$using \: point \: slope \: form \\ y - y1 = m(x - x1) \\ y + 9= \frac{ - 4}{3} (x - 9) \\ y + 9= \frac{ - 4}{3}x + 12\\ y = \frac{ - 4}{3} x + 3$

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2 years ago

Read 2 more answers

I just need help explaining it. solve the system of equation

Maksim231197 [3]

SOLUTION

Write out the equation

$\begin{gathered} y=\frac{1}{3}x-3 \\ 5x-3y=-3 \end{gathered}$

To solve this system of equation, the aprropriate method will be substitution

Substitute the expression for y into the second equation for y, we have

$5x-3(\frac{1}{3}x-3)=-3$

Expand the paranthesis we have

$\begin{gathered} 5x-x+9=-3 \\ \text{Simplify},\text{ by subtracting 9 from both sides } \\ 4x+9-9=-3-9 \\ 4x=-12 \end{gathered}$

Divide both sides by 4, we have

$\begin{gathered} \frac{4x}{4}=-\frac{12}{4} \\ \text{Then} \\ x=-3 \end{gathered}$

Since the value of x has been obtained, we substitute into the first equation

$\begin{gathered} y=\frac{1}{3}x-3 \\ \text{ recall x=}-3 \\ y=\frac{1}{3}(-3)-3 \\ y=-1-4 \\ \text{Hence } \\ y=-4 \end{gathered}$

Therefore

x = -3, y= -4

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8 months ago

Write an equation in point-slope form of the line through the point (−1, 2) and with slope m = 2.

Katen [24]

Answer:

D. y - 2 = 2(x + 1)

Step-by-step explanation:

y - 2 = 2 (x - (-1))

y - 2 = 2 (x + 1)

<h3>#CMIIW</h3>

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2 years ago

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Serga [27]

Answer:

Step-by-step explanation:

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the discrinant of the quadratic equation is : delta = b²-4ac

when a=-2 and b=8 and c= -8

calculate delta = (8)²-4(-2)(-8) ......continu

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2 years ago