Answer:
this reaction is a double displacement reaction in which, Aluminium nitrate reacts with hydrogen sulphide to form nitric acid and Aluminium sulphide.
here is the balanced chemical equation for the above reaction :
2 Al (NO3)3 + 3 H2S -> 6 HNO3 + Al2S3
Answer:
61.3 g/mol
Step-by-step explanation:
We can use the <em>Ideal Gas Law</em> to solve this problem:
pV = nRT
Since n = m/M, the equation becomes
pV = (m/M)RT Multiply each side by M
pVM = RT Divide each side by RT
M = (mRT)/(pV)
<em>Data:
</em>
m = 0.675 g
R = 0.0.083 14 bar·L·K⁻¹mol⁻¹
T = 0 °C = 273.15 K
p = 1 bar
V = 250 mL = 0.250 L
<em>Calculation:
</em>
M= (0.675 × 0.083 14 × 273.15)/(1 × 0.250)
M= 15.33/0.250
M= 61.3 g/mol
It is 14, plug it in or use inverse equations. Since they're vertical angles they are the same value. 41 = 2x+13, 28 = 2x (subtract 13), 14 = x (divide by 2).
The answer is D. Technetium-99m
Given the balanced chemical equation for combustion of propane:
Moles of propane 
=3.6 mol
Propane is the limiting reactant as the other reactant oxygen is said to be present in excess.
Amount of products formed would depend on the moles of limiting reactant.
Mole ratio of water to propane as per the balanced chemical equation
=
Calculating the moles of water produced from 3.6 mol propane:
= 14.4mol
Theoretical yield of water = 14.4 mol
Actual yield = 12 mol
Percent yield = 
= 
