Well I’m. Or to sure but it can’t be B because when you throw the ball the the kinetic energy is still increasing
Answer:
there is 2% of hydrogen and 98% of nitrogen (mass percent)
Explanation:
assuming ideal gas behaviour
P*V=n*R*T
n= P*V/(R*T)
where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)
thus
n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles
since the number of moles is related with the mass m through the molecular weight M
n=m/M
thus denoting 1 as hydrogen and 2 as nitrogen
m₁+m₂ = mt (total mass)
m₁/M₁+m₂/M₂ = n
dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁
w₁/M₁+w₂/M₂ = n/mt
w₁/M₁+(1-w₁) /M₂ = n/mt
w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂)
replacing values
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)
and w₂= 1-w₁= 0.98 (98%)
thus there is 2% of hydrogen and 98% of nitrogen
Answer:2py + 2py -----> Ï2py + Ï*2py
2px + 2px -----> Ï2px + Ï*2px
Explanation:
Molecular orbitals are constructed from atomic orbitals by linear combination of atomic orbitals. The 1s, 2s and 2pz orbitals overlap in an end to end manner hence they only form sigma bonding and anti bonding orbitals. The 2px and 2py orbitals overlap side by side and form pi bonding and anti bonding orbitals. Hence the answer.
Balanced equation: 10 CaCo3 + 20 HCl = 10 CaCl2 + H20 + 15 Co2
Answer:
816L adicionales para mantener la concentración
Explanation:
<em>Cuánta agua debe adicionar el cuidador para que se mantenga la concentración del desinfectante?</em>
<em />
El desinfectante, NaClO, idealmente debe estar en una concentración de:
35.8g / 1000L = 0.0358g/L
Como el velador agregó 65g de desinfectante, la cantidad de agua necesaria es:
65g * (1L / 0.0358g) = 1816L de agua son necesarios
Asumiendo que el velador agregó 1000L, el cuidador debe agregar:
1816L - 1000L =
<h3>816L adicionales para mantener la concentración</h3>