Question

In human population X, consider the simple Mendelian trait for freckles. F is the dominant allele and f is the recessive allele. Individuals who are homozygous dominant (FF) or heterozygous (Ff) for the trait express freckles. Individuals who are homozygous recessive (ff) for the trait do not express freckles. In this population, 30% (0.3) of the alleles are recessive (f) and 70% (0.7) are dominant (F). Use the Hardy-Weinberg equation to determine the genotype frequencies we should expect in the next generation.

Answer 1

Answer:

The genotype frequencies are:

49% FF

9% ff

42% Ff

Explanation:

Let P be the dominant allele and let q be the recessive allele, therefore:

P(F) = 0.7

q(f) = 0.3

P^2 = 0.7^2 = 0.49, 49% FF

q^2 = 0.3^2 = 0.09, 9% ff

2p*q = 2*0.7*0.3 = 0.42, 42% Ff

p^2 + 2p*q + q^2 = 1

0.49 + 0.42 + 0.09 = 1