I believe that the ice cube, being that it still has almost all of its properties, would still have a mass of 25 g after melting
The substance that would be most suitable for row 3 is SODIUM CHLORIDE.
The periodic table is made up of groups and periods, the periods are also called rows. There are seven rows and 18 groups in the periodic table. The third period is made up of 8 elements; both sodium and chlorine are part of the eight elements, thus, sodium chloride is more likely to be found on the third row.
Answer:
Compare the solubility of silver iodide in each of the following aqueous solutions:
a. 0.10 M AgCH3COO
b. 0.10 M NaI
c. 0.10 M KCH3COO
d. 0.10 M NH4NO3
1. More soluble than in pure water.
2. Similar solubility as in pure water.
3. Less soluble than in pure water.
Explanation:
This can be explained based on common ion effect.
According to common ion effect the solubility of a sparingly soluble salt decreases further in a solution which has a common ion to it.
The solubility of AgI(s) silver iodide in water is shown below:
a. a. 0.10 M AgCH3COO has a common ion Ag+ with AgI.
So, AgI is less soluble than in pure water in this solution.
b. 0.10 M NaI has a common ion I- with AgI.
So, AgI is less soluble than in pure water in this solution.
c. 0.10 M KCH3COO:
This solution has no common ion with AgI.
So, AgI has similar solubility as in pure water.
d. 0.10 M NH4NO3:
In this solution, AgI can be more soluble than in pure water.
Answer 1:
Correct Answer: Option A i.e. <span>The temperature stays constant for a while, then rises (A).
Reason:
At 0 oC, H2O exist in dual state (solid and liquid) i.e. there exist an equilibrium between ice and water. Hence, when the heat is supplied, it is initially used to bring about phase transformation from solid to liquid state. During this time, temperature remains constant. Once the phase transformation has occurred, heat is utilized for increasing the temperature of system i.e. water.
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Answer 2:
Correct Answer: Option </span><span>B) At first, the energy supplied goes into overcoming attractive forces in the solid. </span><span>
Reason:
In the present case, initially</span> the energy supplied goes into overcoming attractive forces in the solid. Once the ice is converted into water, it now exist in single phase i.e .liquid. Hence, now when further heat is supplied to the system, it is used only for increasing the temperature of system.
We have 25cm^3 of 0.1mol AgNO3.
25cm^3 = 0.025L, so we have 0.025 x 0.1 = 0.0025mol AgNO3, so
0.0025AgNO3 + 0.0025NaCl = 0.0025AgCl + 0.0025NaNO3
Change in Free Energy: ΔG(20C) = -0.064kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -0.110kJ (negative, so the reaction is exothermic)
This reaction produces 0.358g of AgCl and 0.213g of NaNO3
Les Mclean PhD
