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shusha [124]
3 years ago
6

Need help ASAP DUE IN LIKE 2 minutes!!!!!!! Points are added

Chemistry
1 answer:
I am Lyosha [343]3 years ago
7 0

Proton:

Positive

Found in Nucleus

Mass of 1 AMU

Neutron:

Neutral

Found in Nucleus

Mass of 1 AMU

Electron:

Negative

Found in orbitals

Mass of 0 AMU

Please mark Brainliest if this helped you! :)

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The atomic mass of helium-4 is 4.0026 amu. How many of each
umka21 [38]

Answer:

Protons: 2.

Electrons: 2.

Neutrons: 2.

Explanation:

Hello,

In this case, since an atom's atomic number is equal to the number of electrons, considering the electron configurations, taking into account that helium-4 is neither positively nor negatively charged, we can infer that the number of electrons equal the number of protons, which in this case are 2, due to the fact that is atomic number is 2.

Moreover, as helium-4's atomic number is 4 as a whole number, we compute the number of neutrons by using the shown below equation:

Neutrons=mass\ number-atomic\ number\\\\Neutrons=4-2\\\\Neutrons=2

Regards.

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3 years ago
Which is an example of a polymer?
g100num [7]

Answer:

diamond

Explanation:

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Complete the paragraph below. Do it using your Science journal or notebook
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Answer:

SUSPENSION IS A KIND OF MIXTURE where particlea are visible to the naked eyes AS IT settled AT THE BOTTOM WHEN LEFT UNDISTURBED.

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3 years ago
When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

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2 years ago
What is the molarity of the nitric acid solution if 20.5 mL of a 0.125 M lithium hydroxide solution are needed to titrate a 25.0
sveticcg [70]

Answer:: We're asked to find the molar concentration of the NaCl solution given some titration data.

Explanation:

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