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3 years ago

What is the molecular formula for C5H7 if its molar mass is 536 g/mol?

Chemistry

1 answer:

hodyreva [135]3 years ago

8 0

Answer:

(C5H7)8

Explanation:

It's empirical formula is given as; C5H7

Molar mass of carbon(C) = 12 g/mol

Molar mass of hydrogen(H) = 1 g/mol

We are told that it's molar mass is 536 g/mol.

To find the molecular formula;

Molecular formula = n × empirical formula

Thus;

n = 536/((12 × 5) + (1 × 7))

n = 8

Thus;

Molecular formula = (C5H7)8

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What factors mechanical weathering ?. <br><br><br> Earth Science.

OLga [1]

Answer:

-Growth of plants on the rock.

-Temperature and pressure changes in nature.

-Freezing and thawing of water in cracks of the rock.

-Formation of salt crystals within the rock.

-Burrowing by animals.

those are some factors I know

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4 0

2 years ago

Read 2 more answers

What is the percentage of lithium in lithium carbonate (Li2CO3)?

ale4655 [162]

Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g

% LI = 13.88/73.89*100 = 18.78% perfectly correct.

6 0

3 years ago

Read 2 more answers

You are given a 1.55 g mixture of calcium nitrate and calcium chloride. You dissolve this mixture in 20 mL of water and add an e

irina [24]

Answer:

13.4 (w/w)% of CaCl₂ in the mixture

Explanation:

All the Cl⁻ that comes from CaCl₂ (Calcium chloride) will be precipitate in presence of AgNO₃ as AgCl.

To solve this problem we must find the moles of AgCl = Moles of Cl⁻. As 2 moles of Cl⁻ are in 1 mole of CaCl₂ we can find the moles of CaCl₂ and its mass in order to find mass percent of calcium chloride in the original mixture.

<em>Moles AgCl - Molar mass: 143.32g/mol -:</em>

0.535g * (1mol / 143.32g) = 3.733x10⁻³ moles AgCl = Moles Cl⁻

<em>Moles CaCl₂:</em>

3.733x10⁻³ moles Cl⁻ * (1mol CaCl₂ / 2mol Cl⁻) = 1.866x10⁻³ moles CaCl₂

<em>Mass CaCl₂ -Molar mass: 110.98g/mol-:</em>

1.866x10⁻³ moles CaCl₂ * (110.98g/mol) = 0.207g of CaCl₂ in the mixture

That means mass percent of CaCl₂ is:

0.207g CaCl₂ / 1.55g * 100 =

<h3>13.4 (w/w)% of CaCl₂ in the mixture</h3>

8 0

3 years ago

A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of

mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.125

t = ?

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.125=e^{-0.00440\times t}$

t = 473 year

8 0

3 years ago

1 how many moles of sodium bicarbonate are needed to neutralize 0.9ml of sulphuric acid at stp

Natali5045456 [20]

Answer:

8.0356 * 10^-5 moles of NaHCO3

Explanation:

Sulphuric acid = H2SO4

Sodium bicarbonate = NaHCO3

The reaction between both compounds is given by;

2NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)

In the reactin above;

2 mol of NaHCO3 neutralizes 1 mol of H2SO4

At stp, 1 mol occupies 22.4 L;

1 mol = 22.4 L = 22400 mL

x mol = 0.9 mL

x = 0.9 / 22400 = 4.0178 * 10^-5 moles of H2SO4

Since 2 mol = 1 mol from the equation;

x mol = 4.0178 * 10^-5

x mol = 2 * 4.0178 * 10^-5

x = 8.0356 * 10^-5 moles of NaHCO3

3 0

3 years ago