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3 years ago

What is the mass of 4.5 moles of nitrogen gas

Chemistry

1 answer:

Citrus2011 [14]3 years ago

6 0

n = m / M

m = n × M

Nitrogen (N2) - a gas is always with an index 2 if we don't have shown how many molecules are there

m (N2) = 4,5 mol × (2×14.007 g/mol)

m (N2) = 4,5 mol × 28.014 g/mol = 126.063g

if you don't solve with the decimals in class just replace 14.007 with 14

also if you haven't learned abour gasses aways having index 2 then:

m (N2) = 4,5 mol × 14.007 g/mol = 63.0315g

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You are given a liquid. Briefly describe the steps you would take to show whether it is a pure substance or a homogeneous mixtur

Brums [2.3K]

Answer:

By using any one technique like boiling, distillation, condensation ,etc , one can be used to distinguish between a pure substance and a homogeneous mixture.

Explanation:

If the liquid is a pure substance, then it can not be separated by using physical means because all atoms of a pure substance show same properties.

But on the other hand, if there is homogeneous mixture, it can be separated by using techniques like boiling, distillation, condensation ,etc.

<u>Thus, using any of the one method listed above can be used to distinguish between a pure substance and a homogeneous mixture.</u>

3 0

3 years ago

will give brainliest!! please help ! .. Calculate the total pressure of the mixture in atmospheres ( atm ).

nordsb [41]

Answer:

13.94 atm

Explanation:

From the question given above, the following data were obtained:

Pressure of H₂ = 2 atm

Pressure of NH₃ = 303 KPa

Pressure of CO₂ = 3000 mmHg

Pressure of N₂ = 3800 torr

Total pressure (Pₜ) in atm =?

Next, we shall convert 303 KPa, 3000 mmHg and 3800 torr to atm.

This can be obtained as follow:

Converting 303 KPa to atm

101.325 KPa = 1 atm

Therefore,

303 KPa = 303 KPa × 1 atm / 101.325 KPa

303 KPa = 2.99 atm

Thus, 303 KPa is equivalent to 2.99 atm.

Converting 3000 mmHg to atm

760 mmHg = 1 atm

Therefore,

3000 mmHg = 3000 mmHg × 1 atm / 760 mmHg

3000 mmHg = 3.95 atm

Thus, 3000 mmHg is equivalent to 3.95 atm

Converting 3800 torr to atm

760 torr = 1 atm

Therefore,

3800 torr = 3800 torr × 1 atm / 760 torr

3800 torr = 5 atm

Thus, 3800 torr is equivalent to 5 atm.

Finally, we shall determine the total pressure of the mixture as follow:

Pressure of H₂ (P₁) = 2 atm

Pressure of NH₃ (P₂) = 2.99 atm

Pressure of CO₂ (P₃) = 3.95 atm

Pressure of N₂ (P₄) = 5 atm

Total pressure (Pₜ) in atm =?

Pₜ = P₁ + P₂ + P₃ + P₄

Pₜ = 2 + 2.99 + 3.95 + 5

Pₜ = 13.94 atm

Therefore, the total pressure of the mixture is 13.94 atm

4 0

3 years ago

Tungsten (W) and chlorine (Cl) form a series of compounds with the following compositions:_______.

deff fn [24]

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine = 361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

4 0

3 years ago

Which type of scientist makes use of the reaction of carbonates with acids?

Romashka-Z-Leto [24]

Answer:

geologists

Explanation:

they use acid test in order to determine if the sample is a carbonate.

8 0

3 years ago

Read 2 more answers

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$

3 0

3 years ago