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IgorC [24]
3 years ago
15

He takes a random sample of 49 recent charterholders and computes a mean salary of $172,000 with a standard deviation of $35,000

. Use this sample information to determine the 90% confidence interval for the average salary of a CFA charterholder.
Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer:

the 90% of confidence intervals for the average salary of a CFA charter holder

 (1,63,775 , 1,80,000)

Step-by-step explanation:

<u>Explanation</u>:-

random sample of n = 49 recent charter holders

mean of sample (x⁻) =  $172,000

standard deviation of sample( S) = $35,000

Level of significance α= 1.645

<u> 90% confidence interval</u>

(x^{-} - Z_{\alpha } \frac{s}{\sqrt{n} } , x^{-} + Z_{\alpha } \frac{s}{\sqrt{n} })

(172000 - 1.645 \frac{35000}{\sqrt{49} } , 172000 +1.645 \frac{35000}{\sqrt{49} })

on calculation , we get

(1,63,775 , 1,80,000)

The mean value lies between the 90% of confidence intervals

(1,63,775 , 1,80,000)

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Sauron [17]
Ok so

8000=cost
profit-8000
then
another cost is 15rand per mug
but profit of 35 rand
35-15=20
profit of 20rand per mug

profit=R20m-R8000
where m=number of mugs sold
(R20 means 20 rand)


f(m)=R20m-R8000

break even means cost=earned
basically, when profit=0
0=R20m-R8000
add 8000 to both sides
R8000=R20m
divide both sides by 20
400=m

break even is 400 mugs


graph should be easy enough
put a point at (0,-8000) and at (400,0) then connect them



profit
f(x)=R20x-R8000
break even is 400 mugs

put points (0,-8000) and (400,0) and connect them
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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IRISSAK [1]

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Step-by-step explanation:

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4 years ago
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