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3 years ago

6x+5y+2z=41 4x-10z=-10 -x-2y+2z=-1

Mathematics

1 answer:

ikadub [295]3 years ago

6 0

\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[1585y+796z] totally answer

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9(2x-1)=3(x+2)+3x solve the equation thanks so much for your help guys or girls you have no idea how helpful it is :)

stealth61 [152]

9(2x-1)=3(x+2)+3x

18x-9=3x+6+3x

18x-9=6x+6

18x-6x=6+9

12x=15

x=15/12

x=5/4

5 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago

If tan x =1/2<br> find sin x<br> 2

irina1246 [14]

Answer:

∘

360

∘

Step-by-step explanation:

tan

Calculator and unit circle give 2 solutions for (0, 360) -->

∘

, and

180

26.57

206

∘

General answer:

∘

360

∘

6 0

3 years ago

8x - y = 50; x + 4y = -2

inessss [21]

Answer: x= 6, y= -2

Step-by-step explanation: hope this helps.

3 0

3 years ago

Read 2 more answers

What is the range of the relation?

Bas_tet [7]

They are on quarenent one

7 0

3 years ago