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Bogdan [553]
3 years ago
15

6x+5y+2z=41 4x-10z=-10 -x-2y+2z=-1

Mathematics
1 answer:
ikadub [295]3 years ago
6 0
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​] totally answer
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Answer:

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Step-by-step explanation:

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For Exam 2:

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<u>The z-scores for both the tests are same hence the third option is correct i.e. </u><u>you did the same on both exams.</u>

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