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2 years ago

13

What would be the cash balance in the general ledger if a credit of $2,000 is posted to the cash account that had a beginning ba

lance of $10,000 before posting?

1 answer:

frez [133]2 years ago

8 0

A debit of 8000. It would make sense that a credit in cash would decrease the balance, therefore you deduct 2000 from 10000.

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3 years ago

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2 years ago

Suppose that a company needs new equipment, and that the machinery in question earns the company revenue at a continuous rate of

julia-pushkina [17]

Answer:

a-The present value of revenue in the first year is $61,085.92.

b-The total time it would take to pay for its price is 2.44 years of 29.33 months.

Explanation:

a-

Let the function of the revenue earned is given as

$S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt$

Here

a and b are the limits of integral which are 0 and 1 respectively
r is the rate of interest which is 5% or 0.05

S(t) is the function of value which is $S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225$
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as
$PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt+\int\limits^t_1 {S(t)e^{-0.05t}} \, dt\\PV=61085.9225+\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt$
The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:
$PV=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\160000=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt=160000-61085.9225\\\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt=98914.07\\\\t=-\dfrac{\ln \left(0.93034\right)}{0.05}\\t=1.44496$
So the total time it would take to pay for its price is 2.44 years of 29.33 months.

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2 years ago