Call : x - 4y + z = 6 (e1) == > z = 6 - x + 4y 2x + 5y - z = 7 (e2) 2x - y - z = 1 (e3)
sub z from e1 in e2 you have : 2x + 5y - 6 + x - 4y = 7 ==> 3x + y = 13 ==> 3x = 13 - y (*)sub z from e1 in e3 you have: 2x - y - 6 + x - 4y = 1 ==> 3x - 5y = 7 (**)
sub 3x from (*) in (**), you have 13 - y - 5y = 7 ==> 6 = 6y ==> y = 1sub y = 1 into (*), you have: 3x = 13 - 1 = 12 ==> x = 4
sub both y = 1 and x = 4 into (e1), you have: 4 - 4(1) + z = 6 ==> z = 6
so answer : x = 4, y = 1, z =6 (you can use these values to check other equations to see if they come out all right)
1/10+1/10+1/10+1/10+1/10+1/10+1/10 and 3/10+4/10
Answer:
Th Range is [0, -∞)
Step-by-step explanation:
f(x) = 2 - x
w(x) = x - 2
We want to find the range of (f * w)(x).
First, we need to find (f * w)(x), which is the multiplication of the function f(x) and the function w(x). Lets use algebra to find (f * w)(x):

This is a quadratic function (U shaped), or a parabola. The graph is attached.
The range is the set of y-values for which the function is defined.
We see from the graph that the parabola is upside down and the highest value is y = 0 and lowest goes towards negative infinity. So the range is from 0 to negative infinity. Or,
0 < y < ∞
In interval notation, that would be:
[0, -∞)