Kathy goes to a Halloween store that is closing for the season, so everything is 60% off of the original price.

HELPP IM FAILING MATH RN!! LC is 40°. What is the measure of arc CB?

wel

Hi there!

$\large\boxed{100^{o}}$

∠C = 40° and triangle ABC is isosceles, therefore:

∠C = ∠A = 40°

Angles in a triangle sum up to 180°, so:

180 = 40 + 40 + ∠A

180 = 80 + ∠A

100 = ∠A

Thus, arc CB has a measure of 100°.

6 0

3 years ago

Read 2 more answers

Rewa Delta Union RugbyCEOhas become concerned about the slow pace of the rugby gamesplayed inthe current union rugby, fearing th

Alex Ar [27]

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

8 0

3 years ago

Plz answer all measures plz ASAP thx

LiRa [457]

Lines a and b are parallel, so lines p, q, and t are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.

∠1 = 90° — corresponding angle to the right angle above it

∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°

∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)

∠4 = 112° — equal to angle 3

∠5 = 68° — equal to angle 2; supplementary to angle 4

∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle

∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6

∠8 = 124° — alternate interior angle with angle 7, hence its equal.

3 0

3 years ago

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25 ≥ 5u u = 5 True of false ( show work )

iris [78.8K]

Answer:

true

Step-by-step explanation:

plug in u. u=e

25>= 5x5

25>=25

true

6 0

3 years ago

the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons

padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

Upper Limit

$\dfrac{11}{16} + \dfrac{1}{64}$