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4 years ago

Software development process that develops software iteratively with a heavy emphasis on construction activities is known as

1 answer:

7 0

Software development process that develops software iteratively with a heavy emphasis on construction activities is known as an agile process. This process is driven by and focused on customer descriptions. It recognizes that plans are only for a short time and delivers a number of software increments.

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The purpose of planning is setting goals and formulating operational plans to achieve those goals. Managers spend a great deal o

Ivanshal [37]

Answer:

e. program project

Explanation:

programming a project helps you to build a framework for timely executions of plans turning operational plans into goals

6 0

3 years ago

During November, the production department of a process operations system completed and transferred to finished goods 35,000 uni

azamat

Answer:

The number of equivalent units using the weighted-average method is 185,000.

Explanation:

Determine the number of units completed and transferred out.

Number of units completed and transferred out = Units in beginning

+ Units started and completed during the month

=35,000+110,000

=145,000

Therefore, the number of units completed and transferred out is 145,000 units.

It is given that the beginning units completed is 35,000, and the units started and completed are 110,000. They are added to calculate the number of units completed and transferred out. Therefore, the number of units completed and transferred out is 145,000 units.

----

Determine the number of equivalent units using the weighted-average method.

Equivalent units = Number of units completed and transferred out + Additional units in process ×Percentagecompleted

=145,000+(40,000×100%)

=185,000

6 0

3 years ago

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$