Answer: 2 - 2*sin³(θ) - √1 -sin²(θ)
Step-by-step explanation: In the expression
cos(theta)*sin2(theta) − cos(theta)
sin (2θ) = 2 sin(θ)*cos(θ) ⇒ cos(θ)*2sin(θ)cos(θ) - cos(θ)
2cos²(θ)sin(θ) - cos(θ) if we use cos²(θ) = 1-sin²(θ)
2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)
2 - 2sin²(θ)sin(θ) - cos(θ) ⇒ 2-2sin³(θ)-cos(θ) ; cos(θ) = √1 -sin²(θ)
2 - 2*sin³(θ) - √1 -sin²(θ)
2(n - 1) + 4n = 2(3n - 1)
2n - 2 + 4n = 6n -2
6n - 2 = 6n - 2 (equal)
6n - 6n = 2 - 2
0 = 0
whatever value you put into the place of n, you'll get 0 = 0
Cosine theta equals the negative square root of three over two; tangent theta equals the negative square root of three over three is the correct answer.
<h3>What is angle measurement?</h3>
An angle measure is the measurement of the angle created by two rays or arms at a shared vertex in geometry. A protractor is used to measure angles in degrees (°).
Given data;
sin(1/2) = π/6
The value of the trignometric function are;
cos(π/6) = (√3)/2
tan(π/6) = 1/√3 = (√3)/3
In the second quadrant, where the cosine and tangent signs are both negative, is the angle of interest.
θ = 5π/6
cos(5π/6) = -(√3)/2
tan(5π/6) = -(√3)/3
Hence. cosine theta equals the negative square root of three over two; tangent theta equals the negative square root of three over three is the correct answer.
To learn more about the angle measurement, refer to the link;
brainly.com/question/14684647
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Answer:
(2x+5y)(2x+3y)
=(2x)^2 + [5y+3y]2x + (5y)(3y)
=4x^2 +16xy + 15y^2
Step-by-step explanation:
