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Rzqust [24]
4 years ago
5

What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?

Chemistry
1 answer:
victus00 [196]4 years ago
7 0

Answer:

work done = 750 J

Explanation:

Given data:

Force on object = 50 N

Distance covered = 15 m

Work done = ?

Solution:

W = F. d

W = work done

F = force

d = distance

Now we will put the values in formula.

W = 50 N × 15 m

W = 750 N. m = 750 J

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Answer:

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Explanation:

The base to solve this, is the Ideal Gases Law. The mentioned formula is:

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To compare two situations, we can propose:

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As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

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(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg

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