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kipiarov [429]
3 years ago
10

Newton’s second law of motion is F=ma A net force of 60 N north acts on an object with a of 30 kg. Use Newton’s second law of mo

tion to calculate the amount of acceleration the object will experience. Then explain how the amount of acceleration will change if the net force or the mass of the object increases.
Chemistry
2 answers:
horsena [70]3 years ago
8 0
I’m pretty sure the immediate answer is 2. Using the equation 60N=(30kg)x2(whatever unit of measure) also it will change because if you change the mass or the Net Force, your going to have to redo the equation based on the new information.
katrin [286]3 years ago
4 0

Answer:

its 1,875

Explanation:

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¿Cuál es el %m/v de una solución que contiene 5g de NaCl en 750mL de solución?
NemiM [27]
U need to write in English bc can't answer it then
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3 years ago
Consider the following balanced equation: Cu + 2AgNO3 Cu(NO3)2 + 2Ag How many moles of AgNO3 would be needed to produce 2.8 mole
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2.8(2/1)=5.6 moles of AgNO3 would be  needed
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Which statement best describes the roles of photosynthesis and respiration in the carbon cycle?​
BigorU [14]

Answer:

Photosynthesis removes carbon from the atmosphere, and cellular respiration releases carbon back into the atmosphere. Photosynthesis is part of the carbon cycle, and cellular respiration is not. (Only plants perform photosynthesis, and only animals perform cellular respiration )

Explanation:

3 0
3 years ago
Which of the possible compounds has a mass of 163 grams when
Simora [160]

Answer:

CH4

Explanation:

In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.

Hence we can now say;

If 163 g of the compound contains 6.13 ×10^24 molecules

x g will contain 6.02 × 10^23 molecules

x= 163 × 6.02 × 10^23 / 6.13 × 10^24

x= 981.26 × 10^23/ 6.13 ×10^24

x= 160.1 × 10^-1 g

x= 16.01 g

x= 16 g(approximately)

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6 0
3 years ago
What is the minimum mass of ethylene glycol (C2H6O2) that must be dissolved in 14.5 kg of water to prevent the solution from fre
Sergio [31]

Answer : The minimum mass of ethylene glycol is, 12000.2 grams.

Explanation :  Given,

Molal-freezing-point-depression constant (K_f) for water = 1.86^oC/m

Mass of water (solvent) = 14.5 kg

Molar mass of ethylene glycol = 62.07 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of ethylene glycol}}{\text{Molar mass of ethylene glycol}\times \text{Mass of water in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -12.6^oF=-24.8^oC

Conversion used :

^oF=\frac{9}{5}^oC+32

\Delta T^o = freezing point of water = 0^oC

i = Van't Hoff factor = 1 (for non-electrolyte)

K_f = freezing point constant for water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

0^oC-(-24.8^oC)=1\times (1.86^oC/m)\times \frac{\text{Mass of ethylene glycol}}{62.07g/mol\times 14.5kg}

\text{Mass of ethylene glycol}=12000.2g

Therefore, the minimum mass of ethylene glycol is, 12000.2 grams.

6 0
3 years ago
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