Answer:
The answer is C
Step-by-step explanation:
Because that's the answer
Hello there i hope you are having a good day :) Your question : The cost of 12 oranges and 7 couples is 55.36. Eight oranges and apples cost $3.68. Find the cost of each : Firstly you would do oranges = O Apples = A. Then 12 oranges + 7 apples = 5.36 12o + 7A = 5.36 then you would take away from both sides so -12o Take away -12o = 7o = 5.36 - 12A now you would divide this by 7 so 7 cancels each out so you are left with 5.36/ 7 = 0.76 Then it would equal 0.76 - 12o/7 This would equal the amount of apples to be $0.76 each now for the oranges you would do the same that you work out for the apples.
Hopefully that help ya :)
Using PEDMAS, you would divide I/2 first, then add 2 to that and subtract I from the equation. It all varies on what "i" is, however.
Answer:
x = 4
y = 6
z = 5
Step-by-step explanation:
Let
bags of pecans = x
bags of walnuts = y
bags of almonds = z
x + y + z = 15
3x + 3.5y + 4z = 53
Two more bags of walnuts were sold than pecans.
Walnuts = x + 2
x + y + z = 15
3x + 3.5y + 4z = 53
x + x + 2 + z = 15
3x + 3.5(x+2) + 4z = 53
2x + z = 15 - 2
3x + 3.5x + 7 + 4z = 53
2x + z = 13 (1)
6.5x + 4z = 46 (2)
Multiply (1) by 4
8x + 4z = 52 (3)
6.5x + 4z = 46 (2)
Subtract (2) from (3)
8x - 6.5x = 52 - 46
1.5x = 6
Divide both sides by 1.5
x = 4 bags
y = x + 2
= 4 + 2
= 6
y = 6 bags
Substitute the value of x into (1)
2x + z = 13 (1)
2(4) + z = 13
8 + z = 13
z = 13 - 8
= 5
z = 5 bags
Check:
x + y + z = 15
4 + 6 + 5 = 15
