Answer:
Answer is C . GOOD LESSONS♡
Answer:
The unknown compound is a weak acid.
Explanation:
Given that :
a 25 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution.
A buffer region was found around a pH of 3.5. We know that a pH of 3.5 is a weak acid. So, it is likely to be an organic acid
Let assume the solution of the unknown sample to be CH₃COOH
Now :
25 mL of CH₃COOH reacted with 0.115 M of NaOH
The equation for the reaction will be :
CH₃COOH + NaOH -----> CH₃COONa + H₂O
at x mole of 0.115y M of
CH₃COOH NaOH is present
If NaOH was added in excess;
CH₃COOH + NaOH -----> CH₃COONa , NaOH will be lost then CH₃COOH and CH₃COONa will be present
Therefore;
At equilibrium : Only CH₃COONa will be present but if it is above equilibrium NaOH will be present because the pH will increase due to the presence of the strong base
Answer:
Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃
Explanation:
The first step is is to find the limiting reactant; you do this using stoichiometry.
The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.
In this problem, SO₂ is the limiting reactant.
Now to find the theoretical yield we will use the smallest value of SO₃.
I have uploaded a picture to better illustrate the problem and hope it helps.
