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Readme [11.4K]
3 years ago
14

Sally turns on her cellular telephone to speak to her friend who is located thousands of miles away. Which of the following best

describes how such a telephone is able to transmit and receive information?
A. The cellular telephone transmits, receives, and encodes information using only sound waves.
B. The cellular telephone transmits, receives, and encodes information using only electromagnetic waves.
C. The cellular telephone transmits information by electromagnetic waves to a receiver which then encodes them and produces sound.
D. The cellular telephone transmits information by sound waves to a receiver which then encodes them and produces electromagnetic waves.
Physics
2 answers:
Marizza181 [45]3 years ago
7 0

As we know that in cellular phone all the signals are transmitted by antenna in the form of electromagnetic waves

All these electromagnetic waves are transmitted through the phones and then received as a signal to the receiver of another phone

These signals are then processed and converted into sound which is produced by the phone

So here correct answer will be

<em>C. The cellular telephone transmits information by electromagnetic waves to a receiver which then encodes them and produces sound.</em>

svp [43]3 years ago
4 0

Answer:

C

Explanation:

I got the question right on Study Island. Vote me for Brainleist!!!

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anyanavicka [17]

Explanation:

potential energy =360800J

mass(m)=?

height (h)=25m

g=9.8m/s²

we have

potential energy =360800J

mgh=360800J

m×9.8×25=360800

m=360800/(9.8×25)=1472.653061kg

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3 years ago
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Mathematically, relation between force, area and pressure is given by...
Pressure = force / area


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3 years ago
A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

8 0
3 years ago
What happens to the work done when a force is doubled and the distance moved remain the same?​
san4es73 [151]

Answer:

Work done gets doubled.

Explanation:

The work done by a force is given by :

W = Fd

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Inessa05 [86]

Answer: i think the answer is 20.0s

Explanation:

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